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johns420

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johns420

I am trying to write a script that involves finding a file that may have different names but the same file extension. What would be the best way to do this? I need to be able to take the path of the file, file name and extension included, and send it out to a text box.

Thanks for the help in advance

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Jettison

Use FileFindFirstFile() and FileFindNextFile():

$bleh = FileFindFirstFile("*.bat")
If $bleh = -1 Then
    MsgBox(0, "Error", "File/folder not found")
    Exit
EndIf

While 1
    $file = FileFindNextFile($bleh)
    If @error Then ExitLoop
   
    MsgBox(4096, "File:", $file)
WEnd

; Close the search handle
FileClose($bleh)

[font="Impact"]Cats rule, humans drool.[/font]

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johns420

Use FileFindFirstFile() and FileFindNextFile():

$bleh = FileFindFirstFile("*.bat")
If $bleh = -1 Then
    MsgBox(0, "Error", "File/folder not found")
    Exit
EndIf

While 1
    $file = FileFindNextFile($bleh)
    If @error Then ExitLoop
   
    MsgBox(4096, "File:", $file)
WEnd

; Close the search handle
FileClose($bleh)

Awesome, thanks for the help.

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