johns420 Posted July 12, 2007 Posted July 12, 2007 I am trying to write a script that involves finding a file that may have different names but the same file extension. What would be the best way to do this? I need to be able to take the path of the file, file name and extension included, and send it out to a text box. Thanks for the help in advance
Jettison Posted July 12, 2007 Posted July 12, 2007 Use FileFindFirstFile() and FileFindNextFile(): $bleh = FileFindFirstFile("*.bat") If $bleh = -1 Then MsgBox(0, "Error", "File/folder not found") Exit EndIf While 1 $file = FileFindNextFile($bleh) If @error Then ExitLoop MsgBox(4096, "File:", $file) WEnd ; Close the search handle FileClose($bleh) [font="Impact"]Cats rule, humans drool.[/font]
johns420 Posted July 12, 2007 Author Posted July 12, 2007 Use FileFindFirstFile() and FileFindNextFile(): $bleh = FileFindFirstFile("*.bat") If $bleh = -1 Then MsgBox(0, "Error", "File/folder not found") Exit EndIf While 1 $file = FileFindNextFile($bleh) If @error Then ExitLoop MsgBox(4096, "File:", $file) WEnd ; Close the search handle FileClose($bleh) Awesome, thanks for the help.
Recommended Posts
Create an account or sign in to comment
You need to be a member in order to leave a comment
Create an account
Sign up for a new account in our community. It's easy!
Register a new accountSign in
Already have an account? Sign in here.
Sign In Now