Mecano Posted December 10, 2007 Share Posted December 10, 2007 Hallo forum members, I try to find out how to find a exact key from the register RegEnumKey shows the key is there in de Message box So when $var contains Photoshop then the message must be MsgBox(48,"Found","Found Photoshop",2) But it shows No Photoshop","No Photoshop found What Im doing wrong? ;Test if to find out if Photoshop was on this computer #NoTrayIcon For $i= 1 to 10 $var = RegEnumKey("HKEY_LOCAL_MACHINE\SOFTWARE\Adobe", $i) If @error <> 0 then ExitLoop MsgBox(4096, "SubKey #" & $i & " under HKLM\Software: ", $var);Msg box is just an test to see Photoshop is there Next $ff = ($var & "\Photoshop") If $ff = 1 Then MsgBox(48,"Found","Found Photoshop",2) Else MsgBox(64,"No Photoshop","No Photoshop found",2) EndIf Link to comment Share on other sites More sharing options...
mikiutama Posted December 10, 2007 Share Posted December 10, 2007 $ff = ($var & "\Photoshop") If $ff = 1 Then MsgBox(48,"Found","Found Photoshop",2) Else MsgBox(64,"No Photoshop","No Photoshop found",2)EndIffor you info... $ff value is "HKEY_LOCAL_MACHINE\SOFTWARE\Adobe\Photoshop" and not 1 !!that's why you get "No Photoshop found" Link to comment Share on other sites More sharing options...
weaponx Posted December 10, 2007 Share Posted December 10, 2007 I was going to say just do this but if the default value is blank it sets @ERROR (Bug?) : $result = RegRead("HKLM\Software\Adobe\Photoshop", "") If @ERROR Then MsgBox(0,"","Photoshop not found") Else MsgBox(0,"","Photoshop found") EndIf Link to comment Share on other sites More sharing options...
mikiutama Posted December 10, 2007 Share Posted December 10, 2007 or you can do this... ;Test if to find out if Photoshop was on this computer #NoTrayIcon For $i= 1 to 10 $var = RegEnumKey("HKEY_LOCAL_MACHINE\SOFTWARE\Adobe", $i) If @error <> 0 then ExitLoop If $var = "Photoshop" Then MsgBox(48,"Found","Found Photoshop",2) Else MsgBox(64,"No Photoshop","No Photoshop found",2) EndIf ;MsgBox(4096, "SubKey #" & $i & " under HKLM\Software: ", $var);Msg box is just an test to see Photoshop is there Next Link to comment Share on other sites More sharing options...
Mecano Posted December 10, 2007 Author Share Posted December 10, 2007 Thanxs to all for repley I started with this RegRead and didnt work that's why I tried it with RegEnumKey $result = RegRead("HKLM\Software\Adobe\Photoshop", "") If @ERROR Then MsgBox(0,"","Photoshop not found"): Nope Else MsgBox(0,"","Photoshop found") EndIf Doesn't work you have to put the full string in the script ,dont want to use this cause could be as well an other version ----------------------------------------------------------------------------------------------------------------------------------- result = RegRead("HKEY_LOCAL_MACHINE\SOFTWARE\Adobe\Photoshop\9.0", "PluginPath") If @ERROR Then MsgBox(0,"","Photoshop not found") Else MsgBox(0,"","Photoshop found"): Yep EndIf ========================================================================== This script give a loop 4 times an message box the third says found photoshop #NoTrayIcon For $i= 1 to 10 $var = RegEnumKey("HKEY_LOCAL_MACHINE\SOFTWARE\Adobe", $i) If @error <> 0 then ExitLoop If $var = "Photoshop" Then MsgBox(48,"Found","Found Photoshop",2) Else MsgBox(64,"No Photoshop","No Photoshop found",2) EndIf ;MsgBox(4096, "SubKey #" & $i & " under HKLM\Software: ", $var);Msg box is just an test to see Photoshop is there Next ----------------------------------------------------------------------------------------------------------------------------------- the reg code: Windows Registry Editor Version 5.00 [HKEY_LOCAL_MACHINE\SOFTWARE\Adobe\Photoshop\9.0] "FreeBeforeSlopAdjust"=dword:0013ddf0 "FreeSpace"=dword:0009c228 "ApplicationPath"="E:\\Program Files\\Adobe\\Adobe Photoshop CS2\\" "PluginPath"="" Want to make tis one to detect more versions then Photoshop 9 Maybe StringSplit an option? but I'm an newbie with this a little kick in the right direction Link to comment Share on other sites More sharing options...
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