ReFran Posted January 28, 2008 Posted January 28, 2008 Hi, perhaps someone can help. With stringformat("%.f", $value) I can set the decimalplaces to .xx, but how can I set a thousand separtor x,xxx.xx ? Do I have to use a for loop? Best regards, Reinhard
PsaltyDS Posted January 28, 2008 Posted January 28, 2008 Hi, perhaps someone can help. With stringformat("%.f", $value) I can set the decimalplaces to .xx, but how can I set a thousand separtor x,xxx.xx ? Do I have to use a for loop? Best regards, Reinhard It's _StringAddComma:#include <string.au3> $value = 12345.67890 ConsoleWrite("Debug: " & _StringAddComma(stringformat("%.2f", $value)) & @LF) Valuater's AutoIt 1-2-3, Class... Is now in Session!For those who want somebody to write the script for them: RentACoder"Any technology distinguishable from magic is insufficiently advanced." -- Geek's corollary to Clarke's law
Paulie Posted January 28, 2008 Posted January 28, 2008 (edited) You Can try this... #include <String.au3> $Test = 123456789.9876 $Dec = StringRegExp($Test, "\.\d*",1) $Test = StringRegExpReplace($Test,"\.\d*","") $Test=StringRegExpReplace(_StringReverse($Test), "\d{3}", "\0,") $Result=_StringReverse($Test)&$Dec[0] If StringLeft($Result,1) = "," then $Result = StringTrimLeft($Result,1) MsgBox(0,"",$Result) Edited January 28, 2008 by Paulie
ReFran Posted January 28, 2008 Author Posted January 28, 2008 Great! Both works perfectly. Thanks, Reinhard
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