Help with StringRegExp

[RAMzor 0]

I have a string like this: "VERSION3.9.312ASSY1A4E13F0B" or "Major.MinorSystemVersion21.0Test123"

How can I strip special char () and extract DIGIT and dots (3.9.312 or 21.0) only between two word's ?

This not work as required :

$array = StringRegExp($str, "VERSION(.*)ASSY", 1)
MsgBox(0, "***", $array[0])

Edited June 19, 2008 by RAMzor

[Monamo 3]

I have a string like this: "VERSION3.9.312ASSY1A4E13F0B" or "Major.MinorSystemVersion21.0Test123"

How can I strip special char () and extract DIGIT and dots (3.9.312 or 21.0) only between two word's ?

This not work as required :

$array = StringRegExp($str, "VERSION(.*)ASSY", 1)
MsgBox(0, "***", $array[0])

Slight modification of your code, with updated entry for the special character (Chr(7)):

$sSource = "VERSION3.9.312ASSY1A4E13F0B"
$sPattern = "VERSION(.*)ASSY"
$array = StringRegExp(StringReplace($sSource,Chr(7)," "), $sPattern , 1)
MsgBox(0, "***", $array[0])

[zorphnog 6]

Or:

$array = StringRegExp($str, "VERSION\D*((?:\d|\.)+)\D*ASSY", 3)
If @error = 0 Then MsgBox(0, "***", $array[0])

[RAMzor 0]

Thank you very much, it works!

It is very difficult to deal with this syntax.