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Posted

try

$data = $data & Round($j,2) & @CRLF

Thank for the reply , but this code should reach to "1"

and for that mistake in the STEP the cycle is not completed

any ideas?

regards..

-ennio

Posted

im not a guru :D but this IS odd.. ive never seen this.... maybe its the decimal put in there? can you use whole numbers instead?

Posted

Yada yada yada, floating point numbers are imprecise, yada yada yada.

Seriously, I've answered this more times than I care to remember. It is not a bug. It is expected behavior. If you wish to know more I hear there's this thing called the internet that can answer all your "floating point imprecise" questions.

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