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Hawkwing

stringregexp string has parentheses

3 posts in this topic

I think I understand the basics of stringregexp, thanks to neogia's guide, but what if the test string has parentheses?

So if the test string is "test(#)", and I want to have a pattern like "test([1-9])" how do I do that?


The Wheel of Time turns, and Ages come and pass, leaving memories that become legend. Legend fades to myth, and even myth is long forgotten when the Age that gave it birth comes again.

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Hi There!

This is what I came up with first, but we have a very obvious problem. It only returns what is between the parentheses.

Dim $test[6]
$test[0] = 5
$test[1] = "Test (100)"
$test[2] = "Test (200)"
$test[3] = "Test (300)"
$test[4] = "Test (a400)"
$test[5] = "Test (500)"

For $x = 1 To $test[0]
    $array = StringRegExp($test[$x], "Test \((.*?)\)", 3)

    For $i = 0 To UBound($array) - 1
        MsgBox(0, "RegExp Test with Option 2 - " & $i, $array[$i])
    Next
Next

So I refined the pattern to only return digits:

Dim $test[6]
$test[0] = 5
$test[1] = "Test (100)"
$test[2] = "Test (200)"
$test[3] = "Test (300)"
$test[4] = "Test (a400)"
$test[5] = "Test (500)"

For $x = 1 To $test[0]
    $array = StringRegExp($test[$x], "Test \((\d.*?)\)", 3)

    For $i = 0 To UBound($array) - 1
        MsgBox(0, "RegExp Test with Option 2 - " & $i, $array[$i])
    Next
Next

I'm sure someone will come along with a better regular expression, but I hope this helps somewhat...

Cheers,

Brett

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Thanks! Just went to the helpfile and found out what \ was for, should have done that before I posted :D


The Wheel of Time turns, and Ages come and pass, leaving memories that become legend. Legend fades to myth, and even myth is long forgotten when the Age that gave it birth comes again.

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