# Convert 4 Byte Hex to float(32) or single

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Alright,

I have been banging my head against a wall for days with this one and am finally breaking down and asking for help.

Now before anyone asks, I HAVE searched the whole forum, up and down, for information on this problem and one of the answers provided me 'some' help, but I am still at a loss... so without further a do, here we go.

Post my ideas came from...

I have too convert 3x 4 byte hex values that represent floats. These floats represent a point in three dimensional space, x,y,z coordinates.

0x8D2B33C6 - X Position in space

0x698FC344 - Y Position in space

0xC5524242 - Z Position in space

Now they are currently in network byte order, or Big Endian and need to be converted to Little Endian. So then we have this...

0xC6332B8D

0x44C38F69

0x424252C5 - Respectivly... NOTE: The endian converter in the code handles this with the input, so this is just for ease of reading.

Now using the following code:

```#include <String.au3>
#Include <WinAPI.au3>

\$start = "698FC344"
\$end = hexToFloat(\$start)
MsgBox(0, '', \$end)

func endian_converter(\$value)

local \$byte0 = BitShift(\$value,24)
local \$byte1 = BitAND(BitShift(\$value,-8), 0x00FF0000)
local \$byte2 = BitAND(BitShift(\$value,8), 0x0000FF00)
local \$byte3 = BitShift(\$value,-24)
local \$result = BitOR(\$byte0,\$byte1,\$byte2,\$byte3)
return \$result

endfunc

Func hexToFloat(\$hex)

return StringFormat("%f",_WinAPI_IntToFloat(endian_converter(Number("0x" & \$hex))))

EndFunc```

I get "1564.48156738281" which is correct, however when I replace the hex with this "8D2B33C6" i get "-1.#QNAN" (should be -11466.89)

About HALF of my computations return this "Quiet Not A Number" and I don't know why. I use another program that does hex/binary/float conversions and they all work out correctly there, why not here?

So I guess what I'm asking is why does this not work all the time and why is it returning a QNAN for some of these values? Do I need to create my own HexToFloat32 function? If so, I have run through ALL the wikipedia and google information I can find and still don't understand how to recreate these floats from the hex data.

ANY help would be appreciated here!

Thanks to anyone who takes the time to read this and especially anyone who responds!

~Vaughner

Edited by vaughner
Please click me if you have a minute! Thanks!
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```#include <WinAPI.au3>

Local \$X = 0x8D2B33C6 ; X Position in space
Local \$Y = 0x698FC344 ; Y Position in space
Local \$Z = 0xC5524242 ; Z Position in space

ConsoleWrite(_WinAPI_IntToFloat('0x' & SwapEndian(\$X)) & @CRLF)
ConsoleWrite(_WinAPI_IntToFloat('0x' & SwapEndian(\$Y)) & @CRLF)
ConsoleWrite(_WinAPI_IntToFloat('0x' & SwapEndian(\$Z)) & @CRLF)

; Thank trancexx for this baby, http://www.autoitscript.com/forum/index.php?showtopic=103630
Func SwapEndian(\$iValue)
Return Hex(BinaryMid(\$iValue, 1, 4))
EndFunc```

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```#include <WinAPI.au3>

Local \$X = 0x8D2B33C6 ; X Position in space
Local \$Y = 0x698FC344 ; Y Position in space
Local \$Z = 0xC5524242 ; Z Position in space

ConsoleWrite(_WinAPI_IntToFloat('0x' & SwapEndian(\$X)) & @CRLF)
ConsoleWrite(_WinAPI_IntToFloat('0x' & SwapEndian(\$Y)) & @CRLF)
ConsoleWrite(_WinAPI_IntToFloat('0x' & SwapEndian(\$Z)) & @CRLF)

; Thank trancexx for this baby, http://www.autoitscript.com/forum/index.php?showtopic=103630
Func SwapEndian(\$iValue)
Return Hex(BinaryMid(\$iValue, 1, 4))
EndFunc```
Changed to this for my needs. (I'm pulling the data out of a database, and it didn't work your way. :/)

```#include <WinAPI.au3>

; \$aRow's come from a SQLite Query of my DBase

Local \$X = \$aRow[0] ; X Position in space
Local \$Y = \$aRow[1] ; Y Position in space
Local \$Z = \$aRow[2] ; Z Position in space

\$X = Ptr(\$X)
\$Y = Ptr(\$Y)
\$Z = Ptr(\$Z)

ConsoleWrite(_WinAPI_IntToFloat('0x' & SwapEndian(\$X)) & @CRLF)
ConsoleWrite(_WinAPI_IntToFloat('0x' & SwapEndian(\$Y)) & @CRLF)
ConsoleWrite(_WinAPI_IntToFloat('0x' & SwapEndian(\$Z)) & @CRLF)

; Thank trancexx for this baby, http://www.autoitscript.com/forum/index.php?showtopic=103630
Func SwapEndian(\$iValue)
Return Hex(BinaryMid(\$iValue, 1, 4))
EndFunc```

Seems when you define your value in the program.. IE: Local \$X = 0xf3278343 that \$X represents the pointer already? But when you pull the value from an external source, it only contains the value. This forces the pointer to be returned and allows the WinAPI_IntToFloat to proceed properly.

Thanks Again!

Please click me if you have a minute! Thanks!
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Did you also come by this website?

http://babbage.cs.qc.edu/IEEE-754/32bit.html

If you look into the source of the website and you're able to translate the source you should be able to build your own conversionthingy.

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Thanks notsure, I have just saved a copy of the source of that page for future reference.

I hope this topic makes it clear for anyone needing hexToFloat conversions in the future. I even tried to title it so others can search it easily!

Personally, I'm turning it into a UDF so I don't have to worry about it again!

Please click me if you have a minute! Thanks!

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