why does _FileWriteToLine not work

[Merchants]

some how this does not work any one know why ?

#include <File.au3>

Global $sIniFile = FileOpen(@ScriptDir & "test.txt", 0)
;Example: Write to line 3 of c:\test.txt REPLACING line 3
_FileWriteToLine($sIniFile, 3, "my replacement for line 3", 1)
;Example: Write to line 3 of c:\test.txt NOT REPLACING line 3
_FileWriteToLine($sIniFile, 3, "my insertion", 0)

Edited October 23, 2010 by Merchants

[Werty]

some how this does not work any one know why ?

#include <File.au3>

Global $sIniFile = FileOpen(@ScriptDir & "test.txt", 0)
;Example: Write to line 3 of c:\test.txt REPLACING line 3
_FileWriteToLine($sIniFile, 3, "my replacement for line 3", 1)
;Example: Write to line 3 of c:\test.txt NOT REPLACING line 3
_FileWriteToLine($sIniFile, 3, "my insertion", 0)

Try putting a path in there.

Untested:

#include <File.au3>

Global $sIniFile = FileOpen(@ScriptDir & "test.txt", 0)
;Example: Write to line 3 of c:\test.txt REPLACING line 3
_FileWriteToLine(@ScriptDir & "/" & $sIniFile, 3, "my replacement for line 3", 1)
;Example: Write to line 3 of c:\test.txt NOT REPLACING line 3
_FileWriteToLine(@ScriptDir & "/" & $sIniFile, 3, "my insertion", 0)

[MrMitchell]

some how this does not work any one know why ?

#include <File.au3>

Global $sIniFile = FileOpen(@ScriptDir & "test.txt", 0)
;Example: Write to line 3 of c:\test.txt REPLACING line 3
_FileWriteToLine($sIniFile, 3, "my replacement for line 3", 1)
;Example: Write to line 3 of c:\test.txt NOT REPLACING line 3
_FileWriteToLine($sIniFile, 3, "my insertion", 0)

If you were just using FileWrite() or FileWriteLine()...

In your FileOpen, your flag is 0 which means open the file in read-only mode. You need to use one of the write modes, check help file for reference.

Also, @ScriptDir doesn't include a trailing backslash \ so you'll need to add one prior to "test.txt".

But since you're using _FileWriteToLine() you would need to specify a hard path for the first parameter like Werty said, so just replace your Global $sIniFile line to:

Global $sIniFile = @ScriptDir & "\text.txt"

It would be more efficient to assign the file path to your $sIniFile variable then continue to use $sIniFile instead of the actual path every time you use the _FileWriteToLine function.

[Merchants]

tryed all 2 post but still does not work...

[taietel]

Try this:

#include <File.au3>
Global $sIniFile = FileOpen(@ScriptDir & "\test.txt",2)
;=== some lines of text to test:
For $i=1 To 10
FileWriteLine($sIniFile,"This is line "&$i)
Next
FileClose($sIniFile)
;=== now your code:
;Example: Write to line 3 of c:\test.txt REPLACING line 3
_FileWriteToLine(@ScriptDir & "\test.txt", 3, "my replacement for line 3", 1)
;Example: Write to line 3 of c:\test.txt NOT REPLACING line 3
_FileWriteToLine(@ScriptDir & "\test.txt", 3, "my insertion", 0)

[UEZ]

#include <File.au3> 
Global $sIniFile = @ScriptDir & "\test.txt"
;Example: Write to line 3 of c:\test.txt REPLACING line 3 
_FileWriteToLine($sIniFile, 3, "my replacement for line 3", 1) 
;Example: Write to line 3 of c:\test.txt NOT REPLACING line 3 
_FileWriteToLine($sIniFile, 3, "my insertion", 0)

Br,

UEZ

Edited October 24, 2010 by UEZ

[taietel]

Merchants, in your first script you have to pass the file (with path) to the _FileWriteToLine function, not the file handle.

Second, the file must exists - see the @Error in case of failure (that's why I wrote a test file in the begining).

[Merchants]

i have the info i need here thx