variable inside ""

[spymare]

hi.

I got this line: $1 = (" --http-user= --http-passwd=")

how can i do this:

$1 = (" --http-user=($test) --http-passwd=")

Can i get a $ inside ""?

[Melba23]

spymare,

If you mean get a literal string with a $ sign within it, then just enclose everything in quotes:

$1 = " --http-user=($test) --http-passwd="

MsgBox(0, "Result", $1)

If you mean insert the value of a variable into a string, then use concatenation:

$test = "fred"

$1 = " --http-user=(" & $test & ") --http-passwd="

MsgBox(0, "Result", $1)

All clear?

M23

[Shaarad]

It is quite obvious.. on the other hand, if you want to use " symbol in some place, you can use this

$quote=chr (34)
msgbox (64, "Message", "My name is " & $quote & "Shaarad" & $quote )

[hannes08]

Or you could use this form:

$1 = ' --http-user=("'$test'") --http-passwd='

MsgBox(0, "Result", $1

[MvGulik]

nevermind.

Edited June 28, 2011 by iEvKI3gv9Wrkd41u

[JohnOne]

Or you could use this form:

$1 = ' --http-user=("'$test'") --http-passwd='

MsgBox(0, "Result", $1

Thats not true is it?

[jvanegmond]

AutoItSetOption("ExpandVarStrings", 1)

$test = "Oh hi"

$1 = " --http-user=($test$) --http-passwd="

MsgBox(0, "Result", $1)

[hannes08]

Thats not true is it?

Well, you got me there. oviously forgot the "&". Sorry

$1 = ' --http-user=("' & $test & '") --http-passwd='

MsgBox(0, "Result", $