Hirvesh Posted September 2, 2012 Share Posted September 2, 2012 Hello, I've got a simple application which stores a path to an application like this: $captureAppPath = "D:\Program Files Portable\FSCapture53\FSCapture53\FSCapture.exe" I have been trying to execute the above application using ShellExecute as follows: ShellExecute(FileGetShortName($captureAppPath)) However, the programs throws an error everytime like the one below: ShellExecute($captureAppPath) ShellExecute(^ ERROR ->14:17:50 AutoIT3.exe ended.rc:1 >Exit code: 1 Time: 2.156 Can anybody help me in understanding what I am doing wrong? Link to comment Share on other sites More sharing options...
JohnOne Posted September 2, 2012 Share Posted September 2, 2012 First you say you are running it like this ShellExecute(FileGetShortName($captureAppPath)) then the error says it has been ran like this ShellExecute($captureAppPath) Which is it, pick one. And for the record both ways work just fine for me. I suggest you post a whole reproducer code. AutoIt Absolute Beginners Require a serial Pause Script Video Tutorials by Morthawt ipify Monkey's are, like, natures humans. Link to comment Share on other sites More sharing options...
Hirvesh Posted September 2, 2012 Author Share Posted September 2, 2012 no worries, solved it :-) Link to comment Share on other sites More sharing options...
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