Passing an URL like an argument of a function

[lockito]

Hi!!

I want to create a function that recieves an URL like argument.

I created the function in this way:

Func test(Const $link1)

And i tried to call the function in these 2 ways:

1) test("https://www.google.com")

2) Call("test", "https://www.google.com")

The script compiles but in execution it returns an error on the callings of the function

Can anybody help me?

[michaelslamet]

Hi,

Try this:

test("https://www.google.com")

Func test($link1)

EndFunc

[markyrocks]

Idk what the desired output is but I'd guess the above isn't going to automatically open ie and enter that into the address bar and go there. That may just be stating the obvious but you never know.

[JohnOne]

The code you wrote here is not failing something else is.

_Test("http://www.autoitscript.com/forum/topic/157061-passing-an-url-like-an-argument-of-a-function/")

Func _Test(Const $Link)
    MsgBox(0,"URL", $Link)
EndFunc

[lockito]

Thank you very much michaelslamet, your solution is perfect!!

[JohnOne]

Except the local variable that you wanted constant, is not constant.