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C++ dll param Handling

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#1 ·  Posted (edited)

I have an exported C++ win32 dll function.
It has 2 parameters of LPTSTR.
It works as I expect when I give it correct params.

If I pass an empty string however ("wstr", ""), it errors out with...


87 (0x57)

The parameter is incorrect.


I tried to handle it like so...

if (!param || param == L"") {
        return 0;

But it does not seem to catch that and the function proceeds, and of course errors out.

I guess it's because there's nothing there to have a pointer to, but my question is, is there way to correctly handle this.

Cheers for reading, and I hope I made sense.


I figured an unsafe way to deal with the param that's expecting a fully qualified path, by testing for ":"

Of course that's just silly.

Edited by JohnOne

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#2 ·  Posted (edited)

Equality of strings will check for the pointers being equal. What you actually want with C strings (character arrays) when checking for null or empty is this.

if (!param || !*param)

This will check to see if the pointer is null, and if it isn't, checks to see if the first character pointed to is null.

If it's supposed to be a path, you should probably validate it using this

Edited by Richard Robertson
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