Renderer Posted July 6, 2016 Posted July 6, 2016 Hello there ! Is there any way to return only the remainder of a number? I mean if i have the Number 2.3, how can i only return the remainder in this case 3? Thanks in advance!
RTFC Posted July 6, 2016 Posted July 6, 2016 @AutoBert: Mod() returns the remainder of a division, which is not what the OP is asking for. Instead, try: $var=2.3 msgbox(0,"test",_DecimalPart($var)) Func _DecimalPart($value) Return $value-Int($value) EndFunc My Contributions and Wrappers Spoiler BitMaskSudokuSolver BuildPartitionTable CodeCrypter CodeScanner DigitalDisplay Eigen4AutoIt FAT Suite HighMem MetaCodeFileLibrary OSgrid Pool RdRand SecondDesktop SimulatedAnnealing Xbase I/O
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