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Autoit Return the remainder

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Hello there ! 

Is there any way to return only the remainder of a number? I mean if i have the Number 2.3, how can i only return the remainder in this case 3?

Thanks in advance!

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@AutoBert: Mod() returns the remainder of a division, which is not what the OP is asking for.

Instead, try:

$var=2.3
msgbox(0,"test",_DecimalPart($var))

Func _DecimalPart($value)
    Return $value-Int($value)
EndFunc

 

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