Only action if BOTH keys pressed

[Gaffgarion]

i found this script by melba23 and its exactly what i wanted > link

#include <Misc.au3>
#include <MsgBoxConstants.au3>

Local $hDLL = DllOpen("user32.dll")

HotKeySet("{q}","_Start") ; Fire HotKey on q key
HotKeySet("{ESC}", "_Exit")

While 1
    Sleep(10)
WEnd



Func _Start ()

    ; Look for w key
    If _IsPressed("57", $hDLL) Then
        ; Only action if BOTH pressed
        MsgBox($MB_SYSTEMMODAL, "", "Got it")
    EndIf



EndFunc



Func _Exit()
    DllClose($hDLL)
    Exit
EndFunc

 

if im not wrong, if i hold q key first and then press w key, then the output will be messagebox that says "got it"

but when i tested it, it doesnt do anything.

but if i reverse the order, hold w key first, and then press q key, it works.

now i dont know why is this happen, or is this how this script supposed to do? or there's something wrong?

thank you.

 

Edited May 29, 2018 by Gaffgarion

[jdelaney]

This works:

Func _Start ()

    ; Look for w key
    While _IsPressed(51)
        If _IsPressed(57) Then
            ; Only action if BOTH pressed
            MsgBox($MB_SYSTEMMODAL, "", "Got it")
        EndIf
    WEnd

EndFunc

 

[Melba23]

Gaffgarion,

Quote

if im not wrong

I am afraid you are. The script fires the function when the "q" key is pressed - at this point it checks for the "w" key which must have been pressed before the function was fired. All clear? 

M23