Strings

[reggieblanding]

I want to take a path with filename such as (C:\Program Files\test\temp\myfile.exe) and extract only the filename into a string.

[Paulie]

I want to take a path with filename such as (C:\Program Files\test\temp\myfile.exe) and extract only the filename into a string.

well, this will get the filename from the end of any normal filepath

MsgBox(0, "File Name From Path", "Input: 'C:\Program Files\test\temp\myfile.exe'"& _
@CRLF&"Output: '"& _FileFromPath("C:\Program Files\test\temp\myfile.exe")&"'")

Func _FileFromPath($s_Path)
$Split = StringSplit($s_Path, "\")
Return $Split[$Split[0]]
EndFunc

Edit: Last second forum format

Edited February 24, 2007 by Paulie

[xcal]

Or...

MsgBox(0, "File Name From Path", "Input: 'C:\Program Files\test\temp\myfile.exe'"& _
@CRLF&"Output: '"& _FileFromPath("C:\Program Files\test\temp\myfile.exe")&"'")

Func _FileFromPath($s_Path)
Return StringTrimLeft($s_Path, StringInStr($s_Path, '\', 0, -1))
EndFunc

[SmOke_N]

Ummm.... Something wrong with _PathSplit()?

[Paulie]

Ummm.... Something wrong with _PathSplit()?

well, other than the fact that neither I, nor apparently xcal or reggieblanding knew it existed. nope.

[SmOke_N]

well, other than the fact that neither I, nor apparently xcal or reggieblanding knew it existed. nope.

I've done that before... actually with this exact function (And Valuater and I did exactly what you and xcal did )

[MrCreatoR]

Why don't use RegExp, in this case it the best solution ...

StringRegExpReplace("C:\Program Files\test\temp\myfile.exe", '^.*\\', '')

[xcal]

Ummm.... Something wrong with _PathSplit()?

For the record, I actually know about _PathSplit().

Just wouldn't include all the file udfs for only wanting the filename.

Edited February 24, 2007 by xcal