Fast timer

[Hest 0]

I want to make a clock that runs X times faster than normal, but I'm a bit confused about how to approach. What is the best way to do this?

[Dampe 0]

Have a look at TimerInit() and the other Timer() functions in the help file, I'd say that is your best bet.

Quick and dirty example:

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Local $Timer1, $Timer2
Local $Hours1=0, $Hours2=0, $Minutes1=0, $Minutes2=0, $Seconds1=0, $Seconds2=0

Local $Timer1 = TimerInit()
Local $Timer2 = TimerInit()
Local $FirstProc =0 , $SecondProc=0


While 1
    
    If TimerDiff ($Timer1) >= 1000 Then
        $Timer1= TimerInit()
        $Seconds1 += 1
        $Mil1 = 0
    EndIf
    If $Seconds1 = 60 Then
        $Minutes1 +=1
        $Seconds1 = 0
    EndIf
    If $Minutes1 = 60 Then
        $Hours1 +=1
        $Minutes1 = 0
    EndIf
    
    If TimerDiff ($Timer2) >= 500 Then
        $Timer2= TimerInit()
        $Seconds2 += 1
    EndIf
    If $Seconds2 = 60 Then
        $Minutes2 +=1
        $Seconds2 = 0
    EndIf
    If $Minutes2 = 60 Then
        $Hours2 +=1
        $Minutes2 = 0
    EndIf
    
    ToolTip ("Normal timer: " & $Hours1 & ":" & $Minutes1 & ":" & $Seconds1 & @CRLF & "Double speed timer: " & $Hours2 & ":" & $Minutes2 & ":" & $Seconds2, 50, 50, "Timer example")
    
WEnd

[Hest 0]

Thx, I know I have to use the timer functions, but I need a little guidance on how I should approach this scaling. I need the time to run beteween x5 or x8 times faster.

Is the easiest way just to find the time difference and then * 8?

[Dampe 0]

Thx, I know I have to use the timer functions, but I need a little guidance on how I should approach this scaling. I need the time to run beteween x5 or x8 times faster.

Is the easiest way just to find the time difference and then * 8?

That's probably easier actually, I never thought about that

You'll need to do some mod division to make it work that way though.