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j0kky

Assign a value to an array in array element

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j0kky

Hi guys,

talking about array in array, I would like to directly assign a value to an element in an array contained in another array.

While it is quite simple to access the value if it is already setted:

Local $a[3] = [1, 2], $b[2] = [3, 4]
$a[2] = $b
ConsoleWrite(($a[2])[0] & " " & ($a[2])[1] & @CRLF)

If I try to write directly to the element, I get an error:

Local $a[3] = [1, 2]
Local $b[2]
$a[2] = $b
($a[2])[0] = 1

Is assigning first every value of the contained array and then including it in the container the only way?

Edited by j0kky

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UEZ

You need a helper function with ByRef parameter.

 

Simple example:

#include <Array.au3>
Local $a[3] = [1, 2], $b[2] = [3, 4]
$a[2] = $b

ConsoleWrite(($a[2])[0] & " " & ($a[2])[1] & @CRLF)

ModArray($a[2], 0, "Test")

_ArrayDisplay($a[2])

Func ModArray(ByRef $aArray, $iElement, $value)
    $aArray[$iElement] = $value
EndFunc

Otherwise a copy of the array will be created.

Edited by UEZ
  • Like 1

Please don't send me any personal message and ask for support! I will not reply!

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Her 'sikim hıyar' diyene bir avuç tuz alıp koşma!
¯\_(ツ)_/¯  ٩(●̮̮̃•̃)۶ ٩(-̮̮̃-̃)۶ૐ

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j0kky

Thank you for support!

Writing a function with a ByRef param is a smart solution, anyhow it could be useful to directly assign the value to the element.

I'll open a feature request in the bug tracker, maybe in some of the next Autoit version it will be implemented.

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UEZ
3 hours ago, j0kky said:

I'll open a feature request in the bug tracker, maybe in some of the next Autoit version it will be implemented.

Soon is christmas, I would suggest to send the feature list rather to Santa Claus. 


Please don't send me any personal message and ask for support! I will not reply!

Selection of finest graphical examples at Codepen.io

The own fart smells best!
Her 'sikim hıyar' diyene bir avuç tuz alıp koşma!
¯\_(ツ)_/¯  ٩(●̮̮̃•̃)۶ ٩(-̮̮̃-̃)۶ૐ

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trancexx
On ‎19‎.‎11‎.‎2016‎. at 3:29 PM, j0kky said:

Hi guys,

talking about array in array, I would like to directly assign a value to an element in an array contained in another array.

While it is quite simple to access the value if it is already setted:

Local $a[3] = [1, 2], $b[2] = [3, 4]
$a[2] = $b
ConsoleWrite(($a[2])[0] & " " & ($a[2])[1] & @CRLF)

If I try to write directly to the element, I get an error:

Local $a[3] = [1, 2]
Local $b[2]
$a[2] = $b
($a[2])[0] = 1

Is assigning first every value of the contained array and then including it in the container the only way?

What error? If you see error, then it's not by AutoIt because your code is perfectly valid. It's only that the lase line is not an assignment.

There is no error.


♡♡♡

.

eMyvnE

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j0kky
5 minutes ago, trancexx said:

It's only that the lase line is not an assignment.

($a[2])[0] = 1

The problem is exatly that this line is not considered as an assignment, but ($a[2])[0] is correctly parsed when you try to read from it.

Edited by j0kky

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kylomas

@trancexx,

Given

local $a = [1,2,3], $b = ['a','b','c'], $c = [$a,$b]

how would you change the "a" in array $c?

kylomas


Forum Rules         Procedure for posting code

"I like pigs.  Dogs look up to us.  Cats look down on us.  Pigs treat us as equals."

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trancexx
1 hour ago, j0kky said:
($a[2])[0] = 1

The problem is exatly that this line is not considered as an assignment, but ($a[2])[0] is correctly parsed when you try to read from it.

In both cases you read from it. That's the whole thing.


♡♡♡

.

eMyvnE

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trancexx
13 minutes ago, kylomas said:

@trancexx,

Given

local $a = [1,2,3], $b = ['a','b','c'], $c = [$a,$b]

how would you change the "a" in array $c?

kylomas

Just like UEZ did.


♡♡♡

.

eMyvnE

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j0kky
1 hour ago, trancexx said:

In both cases you read from it. That's the whole thing.

Yes, now it is clear, but it sounds strange to me because if you declare a simple array and try to do the same thing, Autoit doesn't read from it but assigns to it the value.

Local $a[2]
$a[0] = 1

 

Edited by j0kky

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trancexx
28 minutes ago, j0kky said:

Yes, now it is clear, but it sounds strange to me because if you declare a simple array and try to do the same thing, Autoit doesn't read from it but assigns to it the value.

Local $a[2]
$a[0] = 1

 

That's because you're showing different case.

What you did earlier was more like this:

Local $a[2]
($a[0]) = 1

What does this do?

 

 

 


♡♡♡

.

eMyvnE

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trancexx

Don't read wrong what I say, I'm just explaining what AutoIt does. I wrote the code, so I would know.
However I did left it in beta stage, and afterward Jon decided he'd release it. I would ask... but he did not :).


♡♡♡

.

eMyvnE

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j0kky

No problem @trancexx, I'm here to learn :)

I'll try to pose the issue in another way (but I think you already get my point):

If I'm working with a simple array:

Local $a[2]
$a[0] = 1
ConsoleWrite(($a)[0] & @CRLF)
ConsoleWrite($a[0] & @CRLF)

ConsoleWrite outputs are identical.

But if I'm dealing with an array into an array:

Local $a[3] = [1, 2], $b[2] = [3, 4]
$a[2] = $b
ConsoleWrite(($a[2])[0] & @CRLF)
ConsoleWrite($a[2][0] & @CRLF)

The second one (obviously) returns an error because it searches for the 2nd dimension of $a.

 

Edited by j0kky

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