Filemove(Solved)

[232showtime]

hi im stuck with this I want to transfer the correct file in the existing folder

#include <File.au3>
#include <AutoItConstants.au3>
#include <Array.au3>
$Read = "C:\New folder (3)"

$FLFiles1 = _FileListToArrayRec($Read, "*.xlsx", $FLTAR_FILES, $FLTAR_NORECUR, $FLTAR_SORT, $FLTAR_NOPATH)
_ArrayDisplay($FLFiles1)
For $i = 0 To UBound($FLFiles1) - 1
    $STR = StringTrimRight($FLFiles1[$i], 5)
    ConsoleWrite($STR & @CRLF)
    $dirS = DirGetSize($Read & "\" & $STR)
    If $dirS = -1 Then
        MsgBox(16, $STR, $dirS)
    Else
        FileMove($Read, $Read & "\" & $STR & "\" & $STR & ".xlsx")
    EndIf
next

I have 3 folders under "C:\New folder (3)" and I have 5 excel files:

folders:

C:\New folder (3)\1

C:\New folder (3)\3

C:\New folder (3)\5

excel files:

1.xlsx (value of column A are all 1)

2.xlsx (value of column A are all 2)

3.xlsx (value of column A are all 3)

4.xlsx (value of column A are all 4)

5.xlsx (value of column A are all 5)

 

 I run the above script and those excel file 1, 3, 5 was transfered in the 1, 3, and 5 folders but the value of transfered file in Column A are  different and file no. 4 and 5 still remains in the folder "C:\New folder (3)".... ???

whats wrong with the script???

 

 

Edited June 13, 2018 by 232showtime

[Subz]

You would have to create the folder for 4 and 5 so you would need to change the last parameter of FileMove to 

8 - Create Folder
Or
9 - Create Folder and/or OverWrite

[232showtime]

hi Subz,

I dont want to create the folder for 4 and 5, all i want is to transfer the excel file with existing folder.

I want to filemove these excel file:

1.xlsx (with value a of 1 in column A) filemove to folder 1

3.xlsx (with value a of 3 in column A) filemove to folder 3

5.xlsx (with value a of 5 in column A) filemove to folder 5

 

if i ran the script file 1, 3, and 5 are trasferred but if you open the transferred excel file the value of column A is different which means the file that was transfered was different and was renamed.

Im really stuck with this I dont know whats wrong with the script.

 

Edited June 12, 2018 by 232showtime

[Subz]

Yeah that confused me 1.xlsx (with value a of 1 in column A) , do you mean within the .xlsx file Column A1 = 1, which Column are you referring too, I didn't think it was the .xlsx file since you never open the file, can you explain further?

[232showtime]

I attached the example. in my side path is under "C:\New folder (3)"

sample.zip

use the above script and change the path you want.

open the file after transferred.

Edited June 12, 2018 by 232showtime

[Subz]

I'm still not sure what you want to happen to 2.xlsx and 4.xlsx but here is the script updated:

#include <Array.au3>
#include <AutoItConstants.au3>
#include <File.au3>
#include <WinAPIShPath.au3>

Local $sFileName, $iDirSize, $sFilePath= "C:\New folder (3)"
Local $aFileList = _FileListToArrayRec($sFilePath, "*.xlsx", $FLTAR_FILES, $FLTAR_NORECUR, $FLTAR_SORT, $FLTAR_NOPATH)
_ArrayDisplay($aFileList)
For $i = 1 To $aFileList[0]
    $sFileName = _WinAPI_PathRemoveExtension($aFileList[$i])
    If FileExists($sFilePath & "\" & $sFileName) = 0 Then
        MsgBox(4096, "Error", $sFilePath & "\" & $sFileName & " folder does not exist.", 5)
        ContinueLoop
    EndIf
    $iDirSize = DirGetSize($sFilePath& "\" & $sFileName)
    If $iDirSize = -1 Then
        MsgBox(16,$sFileName, $sFilePath & "\" & $sFileName & " is empty.", 5)
    Else
        FileMove($sFilePath & "\" & $aFileList[$i], $sFilePath & "\" & $sFileName & "\" & $aFileList[$i])
    EndIf
next

 

[232showtime]

my goal is to transfer the excel file on the existing folder using the script on my first post..

file 1 which contains a text "file 1" should be transferred to folder no 1

file 3 which contains a text "file 3" should be transferred to folder no 3

file 5 which contains a text "file 5" should be transferred to folder no 5

file 2 which contains a text "file 2" should remain on the same folder C:\New folder (3)

file 4 which contains a text "file 5" should remain on the same folder C:\New folder (3)

I dont want to create folder for file 2 and 4 so they should remain on the same folder C:\New folder (3)

 

see attached pictures pictures:

 

 

Edited June 13, 2018 by 232showtime
i got thousands of file that has an existing folder and i have thousands of files that doesnt have a folder. and i dont want to create folder for the other files because i want to check which one has a folder and which one doesnt have....

[Subz]

Which is what my script above does.

[232showtime]

your script is working perfectly, but please can you tell me whats the problem with the script on my first post???

by the way nice line here

$sFileName = _WinAPI_PathRemoveExtension($aFileList[$i])

new to me

thanks @Subz

Edited June 13, 2018 by 232showtime

[Subz]

1. Line 8: The array should be starting at 1 not 0
2. Line 11: You have a condition that says that if the folder size equals -1, why?  Why not just use FileExists function
3. Line 17: Moving the folder "C:\New folder (3)" to "C:\New Folder (3)\x\x.xlsx (where x equals $sFolderName), so basically it was just moving the first file it found into that particular folder, you never specified the filename.

You can see the results of your script here: (I've changed the variables so that they're readable, but the code is the same, although of just used ConsoleWrite to show your syntax.

#include <File.au3>
#include <AutoItConstants.au3>
#include <Array.au3>
$sSourceFolder = "C:\New folder (3)"

$aFileList = _FileListToArrayRec($sSourceFolder, "*.xlsx", $FLTAR_FILES, $FLTAR_NORECUR, $FLTAR_SORT, $FLTAR_NOPATH)
_ArrayDisplay($aFileList)
For $i = 0 To UBound($aFileList) - 1
    ConsoleWrite("Passthrough# := " & $i & @CRLF)
    $sFolderName = StringTrimRight($aFileList[$i], 5)
    ConsoleWrite("$sFolderName := " & $sFolderName & @CRLF)
    $iDirSize = DirGetSize($sSourceFolder & "\" & $sFolderName)
    ConsoleWrite($sFolderName & " - DirSize :=" & $iDirSize & @CRLF)
    If $iDirSize = -1 Then
        ConsoleWrite($sFolderName & " - DirSize :=" & $iDirSize & @CRLF)
    Else
        ConsoleWrite('FileMove("' & $sSourceFolder & ", " & $sSourceFolder & "\" & $sFolderName & "\" & $sFolderName & ".xlsx" & '")' & @CRLF)
    EndIf
next