associated script called path

[kisstom]

Hi,

If I have a script (zipviewer.au3 for example) associated with .zip files how can I get the path the file called from? For example if I have a 'C:\test.zip' file , right click on it and choose open with zipviewer.au3, my script runs and I need the path and file name 'C:\test.zip'.

Sorry, for my English

[kisstom]

OK, I figured out this:

 

Send("^c")
$FilePath = ClipGet()
ToolTip ($FilePath)
Sleep (2000)
ToolTip("")
Exit

 But I'm quite sure there is more elegant solution(s)

[Subz]

You should compile the .au3 file as an executable, then you can use $CmdLine or $CmdLineRaw to capture the path for example:

Compile the following as an zxt.exe

If $CmdLine[0] >= 1 Then    MsgBox(4096, "CmdLine", $CmdLine[1])

Create a file named File.zxt (for testing purposes only)

Right Click the file and Select OpenWith select zxt.exe.

It should now pop up with the path to the zxt file extension.

Hope that makes sense.

Edited October 2, 2018 by Subz

[kisstom]

That's it!

Thank you.