regular expression is not found in dictionary?

[TheAutomator]

Can someone please say me what i'm missing here?

this little problem is driving me crazy!

i feel so stupid that i have to ask this but why does this script thinks that "=" doesn't exist inside the dictionary?

$regex = ObjCreate("VBScript.RegExp")
$regex.Pattern = "="
$regex.Global = True
$regex.IgnoreCase = True


$test = ObjCreate("scripting.dictionary")
$test.add("=", 2)


$sentence = "="
Local $find = $regex.execute($sentence)


for $part in $find
msgbox(0,1,$part.Value)
MsgBox(0,2,$part.Value = "=")
MsgBox(0,3,$test.exists("="))
msgbox(0,4,$test.exists($part)) ;this should be true!
next

 

Thanks for any help

TheAutomator.

Edited February 22, 2015 by TheAutomator

[SadBunny]

$part is not the thing that equals "=", $part.Value is. 

MsgBox(0, 4, $test.exists($part.Value)) ;this should be true!

Edited February 22, 2015 by SadBunny

[TheAutomator]

 

$part is not the thing that equals "=", $part.Value is. 

MsgBox(0, 4, $test.exists($part.Value)) ;this should be true!

 

Ow, i see 

i thought "$part" only would work to.

i'm so confused right now because i was testing it in vbscript in the meantime and have a look at this:

Set regex = New RegExp
regex.Pattern = "="
regex.Global = True
regex.IgnoreCase = True

set test = createobject("scripting.dictionary")
test.add "=", 2

sentence = "="
set find = regex.execute(sentence)

for each part in find
    msgbox part
    msgbox test.exists(part)
next

here "part" really equals "=" 

why isn't this working then?

TheAutomator.

[SadBunny]

I'm not 100% sure about COM object handling in AutoIt, but I guess the problem is that AutoIt has no way to know what field or method to call from the generic COM object to get the toString value.

VBScript is quite a different language. Object oriented, for one. In this case, the RegExp.execute() method returns an object of the type MatchCollection which then your iterator "part" goes through. I guess there is auto-invocation of the .Value getter/field (don't know how that works in VBscript, never used it) when you access it as a string. I.e. it works not because part equals "=", but because the string auto-invoked string representation equals "=".

Note that this is mostly guesswork, mostly based on the example this link: http://www.regular-expressions.info/vb.html

[TheAutomator]

SadBunny,

 

Thanks for the information,

i found out (in vbscript) you have to type ".value" after it to let it work but "part" itself still is a string containing "="..

regards

TheAutomator.