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FileOpenDialog Question...

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This is part of my script :

FileOpenDialog("Check your game for F.S.M",@ProgramFilesDir,"Exe Files (*.exe)",1)

I want to have only the name of .exe file chosed and no fullpath directory

Thanks in advance

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You can do it this way:

$FilePath= "X:\ffg\rt\t\dfg\wanted.exe"
$filename = StringTrimLeft($FilePath,StringinStr($FilePath,"\",1,-1))
MsgBox(0, '', $filename)

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What you are looking for is Stringsplit Function: you split the filepath to get the last filepath split see the code below are you able to understand it?

Run it first.

$var = FileOpenDialog('',@DesktopDir & "\", "Images (*.exe)", 1 + 4 )

If @error Then
    MsgBox(4096,"","No File(s) chosen")
    $var = StringSplit($var,'\') ;Split string by \
    $i = 1 
    While 1
        if $var[$i] = $var[$var[0]] Then ; if var = last split of the string(that is filename) then show it
            MsgBox(0,'$var[' & $i & ']',"" & $var[$var[0]])
            MsgBox(0,'$var[' & $i & ']',"" & $var[$i])
    $i = $i + 1     
Edited by goldenix

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