Convert variable (tomorrow) date to MM/DD/YYYY format

[kawliga751]

I have established how to get tomorrows date however I can't seem to figure out how to format the date into my required format of MM/DD/YYYY.  

I have this:

$today=_DateToDayValue(@YEAR,@MON,@MDAY)
Dim $Y, $M, $D
$tomorrow=_DayValueToDate($today+1, $Y, $M, $D)

The _DateToDayValue seems to have a fixed format.  I've also tried a :

$vardate = _DateAdd( 'd',1, _NowCalcDate())

with a "StringSplit" and/or StringFormat but the _NowCalcDate seems to also be fixed to a YYYY/MM/DD format.

I'm sure I'm missing something simple but am at a loss.

Any help would be MUCH appreciated

 

 

[anthonyjr2]

Have you tried _NowDate?

[Danyfirex]

Hello. Try this.

 

#include <Date.au3>
Local $today=_DateToDayValue(@YEAR,@MON,@MDAY),$Y, $M, $D
Local $tomorrow=_DayValueToDate($today+1, $Y, $M, $D)
$tomorrow= StringFormat("%02i/%02i/%04i", $M,  $D,  $Y)
ConsoleWrite($tomorrow & @CRLF)

Saludos

[kawliga751]

Danyfirex:

This worked PERFECTLY!. I have never seen s StrngFormat like this and, I would've probably NEVER found it on my own. MANY Thanks

[Danyfirex]

You're welcome mate.

 

Saludos

[JDGamboaG]

I had a similar predicament and it has been solved as well. Thank you.

But:

why does it work??! You're putting arguments outside of the function call! to say the least.

[Bilgus]

@JDGamboaG

I see why you are confused but look at it like this

#include <Date.au3>
Local $today
Local $Y
Local $M
Local $D

$today = _DateToDayValue(@YEAR,@MON,@MDAY)

Local $tomorrow

$tomorrow = _DayValueToDate($today+1, $Y, $M, $D) ;< [Y, M, D] those are by reference

$tomorrow = StringFormat("%02i/%02i/%04i", $M,  $D,  $Y)

ConsoleWrite($tomorrow & @CRLF)

this is exactly the same thing posted by Danyfirex just spread out