check if a specific character in string is a digit

[gcue]

Not sure how i can accurately detect if a specific character in a string is a digit.  The problem is that that I'm dealing with strings which contain a mix of numbers and alpha characters - so using the Number function is giving me inaccurate results.  In the example shown below, C results as a number, again because I'm using the Number function on it.  Feel the need to use Number to convert it from a string though.  Not sure how to get around this.

any recommendations?

;~ $sData = "2123abc3234"
$sData = "c2123abc3234"

If StringIsDigit(Number(StringLeft($sData, 1))) = 1 Then
    ConsoleWrite("digit" & @CRLF)
EndIf

Thanks in advance!

Edited March 17, 2022 by gcue

[Nine]

You did edit your post, so am I :

$sData = "2123abc3234"
;$sData = "c2123abc3234"
;$sData = "abcdedghj"

If StringIsDigit(StringLeft($sData, 1)) Then
    ConsoleWrite("digit" & @CRLF)
EndIf

 

Edited March 17, 2022 by Nine

[gcue]

i see whats happening.. in the case shown below - it is not considering it is a digit because its looking at c2 not just 2! duh!

$sData = "c2123abc3234"

If StringIsDigit(StringLeft($sData, 2)) Then
    ConsoleWrite("digit" & @CRLF)
EndIf

so using 

If StringIsDigit(StringTrimLeft(StringLeft($sData, 2),1)) = 1 Then
     ConsoleWrite("digit" & @CRLF)
EndIf

thank you!!!

[mikell]

  On 3/17/2022 at 4:44 PM, gcue said:

it is not considering it is a digit because its looking at c2 not just 2!

Expand  

according to the title this is simpler

If StringRegExp($sData, '^.\d') Then ConsoleWrite("digit" & @CRLF)

 

[gcue]

that works great also!  thank you mikell