StringinStr broken?

[EndFunc]

Every time I try StringinStr, it returns a number. EVen the example helpfile returns 10 instead of the the word that it shows. I have 3.3.0.0

Anybody else have this problem?

[jvanegmond]

xD

StringInStr is SUPPOSED to return a number. It returns the index of the string that is found.

[EndFunc]

xD

StringInStr is SUPPOSED to return a number. It returns the index of the string that is found.

Hmm, am I using it wrong because I don't remember it doing that. What is it supposed do here?

$result = StringInStr("I am a String", "RING")
MsgBox(0, "Search result:", $result)

$location = StringInStr("How much wood could a woodchuck chuck is a woodchuck could chuck wood?", "wood", 0, 3) ; Find the 3rd occurance of "wood"

The number 10 would make no sense.

[SmOke_N]

It starts at the 10th character of the string, it makes perfect sense.

[EndFunc]

It starts at the 10th character of the string, it makes perfect sense.

I see, yeah I understand. Maybe I'm think of StringSplit.

Ok say Im trying to get the folder name in a path and wanting to get the name after the last "\" in the string.

That is what I was attempting to do. It was giving me a number but I believe I got them confused. Any suggestion on how to do this the most efficient way. I was also using a -1 to make it start on the right side which further confused me. lol

[Authenticity]

Dim $aPath_FileName = StringRegExp($sPath, (.+\\)(.+), 3)

This will return the path plus the '\' in the first element of the array and the 'filename.ext' in the second element, or, fail in case of strings like 'Notepad.exe', 'C:\Games\' etc..

Edited February 25, 2009 by Authenticity

[EndFunc]

Dim $aPath_FileName = StringRegExp($sPath, (.+\\)(.+), 3)

This will return the path plus the '\' in the first element of the array and the 'filename.ext' in the second element, or, fail in case of strings like 'Notepad.exe', 'C:\Games\' etc..

Ok I will check it out. I wanted to retrieve the very last folder in the path and single that out and you wont know how long the directory is.

[SmOke_N]

Dim $aPath_FileName = StringRegExp($sPath, (.+\\)(.+), 3)

This will return the path plus the '\' in the first element of the array and the 'filename.ext' in the second element, or, fail in case of strings like 'Notepad.exe', 'C:\Games\' etc..

StringRegExpReplace($sPath, "(.+?[\\/]+)+(.+?\z)", "\2")

[Authenticity]

So StringSplit it and the filename will be $aSplit[$aSpilt[0]] and the last folder in $aSplit[$aSplit[0]-1].

[herewasplato]

... I was also using a -1 to make it start on the right side which further confused me.

$sPath = "c:\1st\2nd\3rd\4th\5th\file.txt"
$last = StringInStr($sPath, "\", 0, -1)
$next2last = StringInStr($sPath, "\", 0, -1, ($last - 1))
$lastFolder = StringMid($sPath, ($next2last + 1), ($last - 1) - $next2last)
MsgBox(0, "StringMid", $lastFolder)

;or per Authenticity

$PathArray = StringSplit($sPath, "\")
MsgBox(0, "StringSplit", $PathArray[$PathArray[0] - 1])

[Ascend4nt]

Since you want two pieces, you can use _PathSplit, or alternatively here's a quick path-split call:

$aSplitPath=StringRegExp($sPath,'([^\\\:]+)',3)

Given C:a folder\a file, it will return an array like this:

[0] = C

[1] = a folder

[2] = a file

Given C:\a\complete\path\filename.ext, it will return

[0] = C

[1] = a

[2] = complete

[3] = path

[4] = filename.ext

Ascen4nt

[WolfWorld]

Is this like the PathSplit or SplitPath (Cant remember) UDF?

If so use that.

[EndFunc]

Thanks all for the suggestions. I actually don't care about the file. There is no file I'm looking for. Just the very last folder/directory. C:\1\2\3\4\5\6\7. So in that, it would be 7, some cases I won't know what the last folder will be. I will play around with these and see what I come up with.

[EndFunc]

So StringSplit it and the filename will be $aSplit[$aSpilt[0]] and the last folder in $aSplit[$aSplit[0]-1].

works great. Thank you for this.