Best way to see if file/folder creation is today?

[Cyri]

I'm trying to figure out the best way to see if a file/folder's creation date is today. This is what I'm currently using.

#include <Date.au3>
$aFileTime = FileGetTime(@WindowsDir, 1)
If StringCompare($aFileTime[0] & "/" & $aFileTime[1] & "/" & $aFileTime[2], _NowCalcDate()) = 0 Then
     MsgBox(0, "", "created today")
EndIf

Is there a better way than that? I played with _DateDiff() as well, but using days it was matching stuff that occured within the last 24 hours and not actually today.

[spudw2k]

You could do this.

_CreatedToday(@WindowsDir)

Func _CreatedToday($varFileFolder)
    $aFileTime = FileGetTime($varFileFolder, 1)
    If $aFileTime[0]&$aFileTime[1]&$aFileTime[2] = @YEAR&@MON&@MDAY Then 
        MsgBox(0, $varFileFolder, "Created today.")
        Return 1
    EndIf
EndFunc

edit: made into func.

Edited December 10, 2009 by spudw2k

[Info]

$open = FileOpenDialog("open", "", "(*)")
If $open = "" Then Exit

$time = FileGetTime($open, 1) ;1=creation

$Year = $time[0]
$Month = $time[1]
$Day = $time[2]

If $Year = @YEAR And $Month = @MON And $Day = @MDAY Then
    MsgBox(64, "", "'" & $open & "' was created today.")
EndIf

[Cyri]

You could do this.

_CreatedToday(@WindowsDir)

Func _CreatedToday($varFileFolder)
    $aFileTime = FileGetTime($varFileFolder, 1)
    If $aFileTime[0]&$aFileTime[1]&$aFileTime[2] = @YEAR&@MON&@MDAY Then 
        MsgBox(0, $varFileFolder, "Created today.")
        Return 1
    EndIf
EndFunc

edit: made into func.

I got so hung up on trying to put the FileGetTime return back into a date format that I forgot I could just compare them using the built-in macros for year, month, and day. I like the function idea. Thanks.