Exiting a Function?

[S1M1S]

I've encountered a snag where I call another function, but I can't get the original one to exit.

For example:

Func1()

Func Func1()
    Func2()
    MsgBox ( 0, "", "Func1" )
EndFunc

Func Func2()
    Func3()
    MsgBox ( 0, "", "Func2" )
EndFunc

Func Func3()
    Func4()
    MsgBox ( 0, "", "Func3" )
EndFunc

Func Func4()
    Func5()
    MsgBox ( 0, "", "Func4" )
EndFunc

Func Func5()
    MsgBox ( 0, "", "Func5" )
EndFunc

But what if I want to call Func2 AND close Func1?

Is there some sort of function which does this:

Func2()
    MsgBox ( 0, "", "Func1" )
EndFunc

Func Func2()
    _Function_Close ( Func1 )
    Func3()
    MsgBox ( 0, "", "Func2" )
EndFunc

Any help would be greatly appreciated

Edited October 23, 2010 by S1M1S

[Melba23]

S1M1S,

Look at the Interrupting a running function tutorial in the Wiki - lots of information on how to it there. But it is a bit more complicated then a single line!

M23

[water]

@Melba23

Once again I'm impressed by the time and effort you've put into the wiki

No one should be allowed to post a question on the forum before having read the wiki as a whole

[BrewManNH]

The code below shows one way of doing it programmatically within your functions:

Func1()
Func Func1()
    $Return = Func2()
    If $Return > 0 Then Return
    MsgBox(0, "", "Func1")
EndFunc   ;==>Func1
Func Func2()
    $Return = Func3()
    If $Return > 0 Then Return
    MsgBox(0, "", "Func2")
EndFunc   ;==>Func2
Func Func3()
    $Return = Func4()
    If $Return > 0 Then Return
    MsgBox(0, "", "Func3")
    Return 1 ; <<<<<<<<<<<<<<<<<<<<<<<  MsgBox in Func2 will not be run
EndFunc   ;==>Func3
Func Func4()
    $Return = Func5()
    If $Return > 0 Then Return
    MsgBox(0, "", "Func4")
EndFunc   ;==>Func4
Func Func5()
    MsgBox(0, "", "Func5")
    Return 1 ; <<<<<<<<<<<<<<<<<<<<<<<  MsgBox in Func4 will not be run
EndFunc   ;==>Func5

You can use this method so that when you return from the previous function you will run whatever comes after the function call depending upon what happens in the called function. An If...Then statement for instance.

[Melba23]

BrewManNH,

I feel your solution is the one the OP was looking for - I had not taken in that he was calling the new functions from within the running one.

Note to self: Look at the code more closely!

M23

[S1M1S]

Hey, I took your advice Melba, don't worry - Though you do realize I had already been to that page...

And thanks a ton BrewManNH - There's only one problem... I created this thread because I wanted to find out how it worked. Your example is great, and I will be able to mimic it whenever I need to - but how the heck does it work!? What does 'Return'ing 1 do? I know what return does, but returning 1!?

Edited October 26, 2010 by S1M1S

[Oneqa]

It doesn't matter what you value you return. What you will do with the return value does. Simply talking you use the return value to evaluate the successful execution of a function or even use the return value for another function execution or just display the value

-EDIT-

you could also use the Return command to exit a function and simply ignore the return value if you don't need it

Edited October 26, 2010 by Oneqa

[S1M1S]

I think I understand you... but why does the MsgBox not run?

*EDIT: Ohhh! I get it now Thanks mate, much appreciated

Edited October 26, 2010 by S1M1S

[BrewManNH]

I think I understand you... but why does the MsgBox not run?

When you jump to Func3 from Func2, the function call is assigned to a variable, in this case $Return. When Func3 ends, it sends the value of 1 back to the calling routine, and the $Return value is now equal to 1 because that is what I told Func3 to "Return" at the end of its execution. I could have set it to "Return" anything, in this case I set it to return the number 1.

The line following the function call is an If...Then statement, that checks the variable $Return, and if its any value that is greater than 0, then it will Return to ITS calling function, rather than continuing the execution of the func2 function. That's why the MsgBox in Func2 won't run because it Returns to Func1 before its ever executed.

I hope that doesn't confuse you too much, I'm horrible at explaining things.

[Oneqa]

note that in func5 it return 1 which will result in skipping msgbox for the function that execute it which is func4.

Func Func4()
    $Return = Func5()
    If $Return > 0 Then Return  ;<=== This is true because func5 is returning 1, will immediately exit Func4

Func4 is returning empty string which is not greater than zero so msgbox will appear:

Func Func3()
    $Return = Func4()
    If $Return > 0 Then Return ;<=== This is not true, will skip to next statement
    MsgBox(0, "", "Func3")  ;<=== This is true because func5 is returning 1

As i said before when you issue return you will immediately exit the function and return the value after the "Return" statement.

[S1M1S]

[Awesomeness]

I hope that doesn't confuse you too much, I'm horrible at explaining things.

It doesn't matter what you value you return. What you will do with the return value does. Simply talking you use the return value to evaluate the successful execution of a function or even use the return value for another function execution or just display the value

-EDIT-

you could also use the Return command to exit a function and simply ignore the return value if you don't need it

Is there a 'like' button around here somewhere?

[/Awesomeness]

Edited October 26, 2010 by S1M1S