gcue Posted November 2, 2010 Posted November 2, 2010 im trying to get the date difference in months and years $months = _DateDiff('M', $start_date, $end_date) $years = $months / 12 how do i figure out how many months there are when its .3 for instance??
water Posted November 2, 2010 Posted November 2, 2010 (edited) What is "its"? years or months? Do you have an example with real dates to test? Edited November 2, 2010 by water My UDFs and Tutorials: Spoiler UDFs: Active Directory (NEW 2024-07-28 - Version 1.6.3.0) - Download - General Help & Support - Example Scripts - Wiki ExcelChart (2017-07-21 - Version 0.4.0.1) - Download - General Help & Support - Example Scripts OutlookEX (2021-11-16 - Version 1.7.0.0) - Download - General Help & Support - Example Scripts - Wiki OutlookEX_GUI (2021-04-13 - Version 1.4.0.0) - Download Outlook Tools (2019-07-22 - Version 0.6.0.0) - Download - General Help & Support - Wiki PowerPoint (2021-08-31 - Version 1.5.0.0) - Download - General Help & Support - Example Scripts - Wiki Task Scheduler (2022-07-28 - Version 1.6.0.1) - Download - General Help & Support - Wiki Standard UDFs: Excel - Example Scripts - Wiki Word - Wiki Tutorials: ADO - Wiki WebDriver - Wiki
Realm Posted November 2, 2010 Posted November 2, 2010 (edited) gcue, If you need a Integer call for both years and months, you could do something like this: $total_months = _DateDiff('M', $start_date, $end_date) $years = Floor($total_months / 12) $months = $total_months-($years*12) Realm Edit: Fixed an error I wrote in the code. Edited November 2, 2010 by Realm My Contributions: Unix Timestamp: Calculate Unix time, or seconds since Epoch, accounting for your local timezone and daylight savings time. RegEdit Jumper: A Small & Simple interface based on Yashied's Reg Jumper Function, for searching Hives in your registry.
gcue Posted November 2, 2010 Author Posted November 2, 2010 (edited) hmm the result of these gives me 1 year and 11 months $start_date = 2008-11-19 00:00:00 $end_date = 2010-11-02 00:00:00 thanks for your help realm! water - sorry i wasnt clear. trying to get a more accurate change in datediff (showing # of years and months - to the nearest month). so like the dates shown above should be 2 years and 0 months? Edited November 2, 2010 by gcue
water Posted November 2, 2010 Posted November 2, 2010 (edited) You only get full months and years so the result is correct! Edited November 2, 2010 by water My UDFs and Tutorials: Spoiler UDFs: Active Directory (NEW 2024-07-28 - Version 1.6.3.0) - Download - General Help & Support - Example Scripts - Wiki ExcelChart (2017-07-21 - Version 0.4.0.1) - Download - General Help & Support - Example Scripts OutlookEX (2021-11-16 - Version 1.7.0.0) - Download - General Help & Support - Example Scripts - Wiki OutlookEX_GUI (2021-04-13 - Version 1.4.0.0) - Download Outlook Tools (2019-07-22 - Version 0.6.0.0) - Download - General Help & Support - Wiki PowerPoint (2021-08-31 - Version 1.5.0.0) - Download - General Help & Support - Example Scripts - Wiki Task Scheduler (2022-07-28 - Version 1.6.0.1) - Download - General Help & Support - Wiki Standard UDFs: Excel - Example Scripts - Wiki Word - Wiki Tutorials: ADO - Wiki WebDriver - Wiki
gcue Posted November 2, 2010 Author Posted November 2, 2010 ooooo ur right! sorry about that realm.. thanks water!!! and thanks again realm =)
Recommended Posts
Create an account or sign in to comment
You need to be a member in order to leave a comment
Create an account
Sign up for a new account in our community. It's easy!
Register a new accountSign in
Already have an account? Sign in here.
Sign In Now