Using Windows date/time pattern

[atzoref]

Hi all,

I have for example this Time pattern: " 2012-06-27 10-37-50 " (YYYY-MM-DD hh-mm-ss)

How can I convert it to an absoulte time, so I can add num of seconds up or dowwn for example

And then convert it back to the pattern (YYYY-MM-DD hh-mm-ss)

Is it possible?

Thanks

[water]

Change the format from YYY-MM-DD HH-MM-SS to YYYY/MM/DD HH:MM:SS and then use function _DateAdd.

$sDate = StringReplace("2012-06-27 10-37-50", "-", "/", 2)
$sDate = StringReplace($sDate, "-", ":", 2)
ConsoleWrite($sDate & @CRLF)

Edited June 27, 2012 by water

[atzoref]

Hi,

I'm using :

Local $iDateCalc = _DateDiff('s', "1970/01/01 00:00:00", $sDate)
MsgBox(4096, "", "Number of seconds since EPOCH: " & $iDateCalc)

iDateCalcNew = iDateCalc + 7

How can I convert this value of iDateCalcNew (Seconds since 1970) back to Date and Time format?

Edited June 27, 2012 by atzoref

[water]

Use this function written by trancexx.

[UEZ]

Try this:

#include <Date.au3>

$sDateStart = "1970/01/01 00:00:00"
$iSeconds = 10
$sNewDate = _DateAdd("s", $iSeconds, $sDateStart )
ConsoleWrite('@@ Debug(' & @ScriptLineNumber & ') : $sNewDate = ' & $sNewDate & @crlf & '>Error code: ' & @error & @crlf) ;### Debug Console

Br,

UEZ