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trescon

@year @Mon @Mday

5 posts in this topic

Hello I have a little big problem.

I made a program that recovers data by ftp from today and back for 2 days;

in practice retrieves the file with date of today, yesterday and the day before yesterday.

So to do this' I used a simple procedure to subtract the days of the date hereof:

$ year = @ YEAR

$ month = @ MON

$ day = @ MDAY

$ date = $ year & $ month & $ day

data_1 $ = $ year & $ month & ($ day - 1)

data_2 $ = $ year & $ month & ($ day - 2)

The procedure has worked for 10-15 days. At any moment when I launch the program (the executable program mean that I have created 15 days ago) the program gives me the variable and the variable $ $ data_1 data_2 are equal to zero, if I debug it tells me that have results for "false".

Because they are ignorant and I was very happy to have done little program and it worked, I explain now you know why 'should not be more'.

Premise that the executable file 'was compiled in both 32-bit and 64 bit (xp and 7) and is used on 4 different pc, and all by the fact that I do not get more' files for the two variables question.

I do not remember if it worked the last time we were still in July. (you know who does not have any control over how many days a month, but since I use it only when I know I can use it :))

Aiutooooo!!

Thanks

Pastebin : http://pastebin.com/YvTRn1xC


Thank You

Alberto

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I am translate with Google.

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Your script wont' work at the start of a month and return an invalid date. Let's say 2012-08-01 would result in 2012-08-00 or even 2012-08--1

Use function _DateAdd to add or subtract dates.


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OK , i have execute script in the day 04/08 , 05/08 , 06/08 , 07/08 ECC. AND NO WORK.

PLEASE , I AM NO SPECK ENGLISH , I AM USE GOOGLE.

THANK YOU


Thank You

Alberto

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I am translate with Google.

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The following example takes the current data and subtracts 1 resp. 2 and assigns it to variables:

#include <date.au3>
$date1 = _DateAdd("d", -1, _NowCalcDate())
$date2 = _DateAdd("d", -2, _NowCalcDate())
ConsoleWrite($date1 & @LF)
ConsoleWrite($date2 & @LF)

My UDFs and Tutorials:

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Active Directory (NEW 2017-04-18 - Version 1.4.8.0) - Download - General Help & Support - Example Scripts - Wiki
OutlookEX (NEW 2017-02-27 - Version 1.3.1.0) - Download - General Help & Support - Example Scripts - Wiki
ExcelChart (2015-04-01 - Version 0.4.0.0) - Download - General Help & Support - Example Scripts
Excel - Example Scripts - Wiki
Word - Wiki
PowerPoint (2015-06-06 - Version 0.0.5.0) - Download - General Help & Support

Tutorials:
ADO - Wiki

 

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#5 ·  Posted (edited)

Properly written (you have spaces where none should be and $s that are out of place) the code you gave works fine. I just added the StringFormat() to set @MDAY to 2 digits.

$year = @YEAR
$month = @MON
$day = @MDAY
$date = $year & $month & $day
$data_1 = $year & $month & StringFormat("%02d",$day - 1)
$data_2 = $year & $month & StringFormat("%02d",$day - 2)
ConsoleWrite("Date: " & $date & @CRLF & "Data_1: " & $data_1 & @CRLF & "Data_2: " & $data_2 & @CRLF)

This however is shorter and does the same thing.

$date = @YEAR & @MON & StringFormat("%02d",@MDAY)
$data_1 = @YEAR & @MON & StringFormat("%02d",@MDAY - 1)
$data_2 = @YEAR & @MON & StringFormat("%02d",@MDAY - 2)
ConsoleWrite("Date: " & $date & @CRLF & "Data_1: " & $data_1 & @CRLF & "Data_2: " & $data_2 & @CRLF)

All that being said; Water is correct in what function to use.

Edited by GEOSoft

George

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