Start Script through other Script(Advanced)

[RaiNote]

Hello :3

How to make that an Script start another special Script which can only be started through this other script not manual 

The 2 Scripts are compiled but only the main can be started manual.

The other must be started through the other and can't be started manual but if it gets that the main Programm gets closed it will instantly close.

And If in the 2nd Script is an Array how can that be loaded through the first Script?

I hope i formulated it well to understand ^-^.

Thanks.

P.S: A Cat loves fish.

[Jos]

Shell script2 with an expected commandline parameter which contains the initial scripts PID and keep on monitoring that during execution of script2.

Simply exit script2 in case this expected commandline parameter isn't there.
 

Jos

Edited May 31, 2015 by Jos

[RaiNote]

But How would this command line look and at all i don't get all of it.^^

[Bowmore]

This very basic example shows one method. It's not 100% but for someone to start the second script manually they would have to know the key value and know you were using this method.

;Script 1
$key = '{B9E447D4-1706-419A-8077-007D39897225}'
Run('C:\code\test\script2.exe ' & $key)

While 1
    Sleep(10)
wend




;Script 2
$key = '{B9E447D4-1706-419A-8077-007D39897225}'
If $CmdLine[0] < 1 Then Exit ; No key provided
If $CmdLine[1] <> $key = '{B9E447D4-1706-419A-8077-007D39897225}' Then Exit ; Invalid key provided


While 1
    Sleep(10)
wend

 

[RaiNote]

Oh thank you very much so it was that easy :o.

Ima stupid cat :3

[water]

Shouldn't this line

If $CmdLine[1] <> $key = '{B9E447D4-1706-419A-8077-007D39897225}' Then Exit ; Invalid key provided

read

If $CmdLine[1] <> $key Then Exit ; Invalid key provided

 

[Jos]

Add the PID like this:

Run('C:\code\test\script2.exe ' & $key & " " & @AutoItPID)

.. and add something like this to your second script

AdlibRegister("Check_Parent",1000)

Func Check_Parent()
    If Not ProcessExists($CmdLine[2]) then Exit
EndFunc

Jos

Edited May 31, 2015 by Jos

[Bowmore]

Shouldn't this line

If $CmdLine[1] <> $key = '{B9E447D4-1706-419A-8077-007D39897225}' Then Exit ; Invalid key provided

read

If $CmdLine[1] <> $key Then Exit ; Invalid key provided

 

​It most certainly should.