yasha Posted September 17, 2018 Posted September 17, 2018 So i have excel files i want to open, my company sends me files as ddmmyy 500.xlsx all in the same folder with the only difference being ddmmyy is there any way to get a variable to work in this program (i am very new to auto it) Global $excelno $excelno= InputBox('new excel','please write the excel no as yymmdd 500') sleep(500) Local $oExcel = _Excel_Open() Local $sWorkbook = J:\OPS\"$excel .xlsx" Local $oWorkbook = _Excel_BookOpen($oExcel, $sWorkbook)
water Posted September 17, 2018 Posted September 17, 2018 (edited) Welcome to AutoIt and the forum! Sure you can let the user select the workbook to process. I suggest something like this: #include <FileConstants.au3> #include <Excel.au3> Local $sWorkbook = FileOpenDialog("Please select workbook to process", "", "Excel Workbooks (*.xlsx)", $FD_FILEMUSTEXIST + $FD_PATHMUSTEXIST) If @error Then Exit msgBox(0, "Error", "File selection returned error " & @error) ; @error = 1 means: So file was selected Local $oExcel = _Excel_Open() Local $oWorkbook = _Excel_BookOpen($oExcel, $sWorkbook) Edited September 17, 2018 by water Should post a working example :> FrancescoDiMuro and yasha 1 1 My UDFs and Tutorials: Spoiler UDFs: Active Directory (NEW 2024-07-28 - Version 1.6.3.0) - Download - General Help & Support - Example Scripts - Wiki ExcelChart (2017-07-21 - Version 0.4.0.1) - Download - General Help & Support - Example Scripts OutlookEX (2021-11-16 - Version 1.7.0.0) - Download - General Help & Support - Example Scripts - Wiki OutlookEX_GUI (2021-04-13 - Version 1.4.0.0) - Download Outlook Tools (2019-07-22 - Version 0.6.0.0) - Download - General Help & Support - Wiki PowerPoint (2021-08-31 - Version 1.5.0.0) - Download - General Help & Support - Example Scripts - Wiki Task Scheduler (2022-07-28 - Version 1.6.0.1) - Download - General Help & Support - Wiki Standard UDFs: Excel - Example Scripts - Wiki Word - Wiki Tutorials: ADO - Wiki WebDriver - Wiki
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