Filter file name with StringRegExp?

[youtuber]

I want to get the file name that says _stripped.au3 at the end of the file
I can't get the file name.

testV5.1_autoit_stripped.au3
testau3_test.au3
dadasdasd.au3
autoit_autoit.au3
test_stripped.txt

#include <File.au3>

$path = @ScriptDir
$filter = "*.au3"

$search = _FileListToArray($path, $filter)
If IsArray($search) Then
    For $i = 1 To $search[0]
        $RegExp = StringRegExp($search[$i], '(?i)([^_]+)_stripped.au3', 3)
        If IsArray($RegExp) Then
            ConsoleWrite($RegExp[0] & @CRLF)
        EndIf
    Next
EndIf

 

Edited June 11, 2019 by youtuber

[iamtheky]

can you just put it in the filter?

#include <File.au3>
#include<Array.au3>

$path = @ScriptDir
$filter = "*_stripped.au3"

$search = _FileListToArray($path, $filter)

_ArrayDisplay($search)

 

Edited June 11, 2019 by iamtheky

[mikell]

$RegExp = StringRegExp($search[$i], '(?i)(.+)_stripped.au3', 3)

[youtuber]

@mikell All name  samplename_stripped.au3
I guess this should be but I'm not sure I would have any problems : (?i).*_stripped.au3

@iamtheky
works yes but i wonder with regex thanks :)

 

[iamtheky]

$path = @ScriptDir
$filter = "*_stripped.au3"

$search = _FileListToArrayRec($path, $filter)

now it uses regex

[mikell]

@youtuber

I used  .+  because I assumed that you have no file with the name "_stripped.au3" , but you can use  .*  as well 
If you remove parenthesis then you don't remove "_stripped.au3" from the filename

 

  On 6/11/2019 at 3:14 AM, iamtheky said:

now it uses regex

Expand  

Yes but it again doesn't allow to remove the filter from the filename. Let's say that using this option or not is left to the OPs choice

[youtuber]

@iamtheky @mikell

If the file name was this, stripped_v3.au3,stripped_v4.au3,stripped_v5.au3,stripped_v5.1.au3,stripped_v5.2.au3 do you think the following filtering is correct?

$filter = "stripped_v*.au3"
$search = _FileListToArrayRec($path, $filter)

or

$filter = "stripped_v?.au3"
$search = _FileListToArrayRec($path, $filter)

otherwise, would it be more accurate to use regex?

$RegExp = StringRegExp($search[$i], 'stripped_v(\d(.*?){1,2}).au3', 3)

 

[iamtheky]

they are all regex, and either can be built to accomodate large buckets of edge cases.  I dont know that there is anywhere to find a preference that isnt pedantic af. 

Edited June 15, 2019 by iamtheky

[mikell]

except that this

(.*?){1,2}

is somewhat inconsistent ( 0 or more chars, lazy, 1 or 2 times ?!? )

Hint : if the translation of the regex in "usual" language makes no sense, this probably means that the regex makes no sense too 

Edited June 15, 2019 by mikell

[youtuber]

Here is a consistent pattern 

Global $Fileversion[6] = ["asdasfasfasd", _
        "stripped_v0.au3", _
        "stripped_v3.au3", _
        "stripped_v4.au3", _
        "stripped_v5.au3", _
        "stripped_v5.1.0.0.au3"]

For $i = 0 To 5
    $RegExp = StringRegExp($Fileversion[$i], 'stripped_v[\d\.]{0,9}.au3', 3)
    If IsArray($RegExp) Then
        ConsoleWrite($RegExp[0] & @CRLF)
    EndIf
Next

 

Edited June 15, 2019 by youtuber

[FrancescoDiMuro]

@youtuber

You shouldn't even escape the dot in the character class, since it's automatically taken as literal character; you should instead escape the one outside the character class, before the file extension:

stripped_v[\d.]\.au3
stripped_v[0-9.]\.au3

[mikell]

  On 6/15/2019 at 1:22 PM, youtuber said:

Here is a consistent pattern

Expand  

Consistent ? yes. Efficient ? no. Just test it on this

Global $Fileversion[6] = ["asdasfasfasd", _
        "stripped_v5.au3", _
        "stripped_v......au3", _
        "stripped_v.....5.au3", _
        "stripped_v15.12.10.10.au3", _
        "stripped_v5....au3"]

Here is the clean way

$RegExp = StringRegExp($Fileversion[$i], 'stripped_v\d+(?:\.\d+)*\.au3', 3)

 

[Nine]

  On 6/15/2019 at 2:04 PM, mikell said:

StringRegExp($Fileversion[$i], 'stripped_v\d+(?:\.\d+)*\.au3', 3)

Expand  

That wouldn't work with "stripped_v5.au3.txt".  But this simple "^stripped_v.+\.au3$" is working, no ?

[mikell]

  On 6/15/2019 at 2:23 PM, Nine said:

That wouldn't work with "stripped_v5.au3.txt".

Expand  

Right. It should be :   'stripped_v\d+(?:\.\d+)*\.au3$'   ( trailing $ added)
You perfectly showed that regex is not as simple as it seems 

 

  On 6/15/2019 at 2:23 PM, Nine said:

this simple "^stripped_v.+\.au3$" is working, no ?

Expand  

this one matches  "stripped_vademecum#;;lol-.au3"  ....

[Nine]

  On 6/15/2019 at 2:44 PM, mikell said:

this one matches  "stripped_vademecum#;;lol-.au3"  ....

Expand  

Ok, I got it.  You want to have a pattern after _v of digits/dot/digits/dot...Nothing else.

[mikell]

Yes. It was not explicit in the OPs requirements but I assumed that what was to be matched was a version number with a correct syntax 

[Nine]

  On 6/15/2019 at 2:54 PM, mikell said:

Yes. It was not explicit in the OPs requirements but I assumed that what was to be matched was a version number with a correct syntax 

Expand  

Alright, make sense. But then you still need to add ^ at the beginning otherwise you would get false positive with "#123;456:.stripped_v5.au3"

[mikell]

Right again 
I was still remembering the first posts of this thread and I focused on the " stripped_v" + version number 

[moosjuice]

I'm sorry to plug my program here but I must, for there is something this hobbyist may have gleamed from its vast reserves if he had known in advance, and therefore not ask this question. Which wastes all our time! That's important!

 

If you look at what I did there, $aRegExSFile, it perfectly matches this situation. 

(((.*)(?=\\)\N)|(\\))(.*?)\z

The only difference is change \z to $, add stripped_v and .au3, and put the .*? in between them.

(((.*)(?=\\)\N)|(\\))(stripped_v)(.*?)(.au3)$

https://www.debuggex.com/r/AwbaT9ONYtDiqO7W

Edited June 15, 2019 by moosjuice

[youtuber]

regex like love