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Implementing FileOpenDialog

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Hello. I'm fairly new to AutoIt, and I was wondering how you would properly implement the FileOpenDialog function to be used whenever a certain button within the program is pressed. Any help is highly appreciated.

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Welcome to AutoIt and the forum!

What have you coded so far?

Here we try to "teach a man to fish, not give him a fish every day".


My UDFs and Tutorials:

Spoiler

UDFs:
Active Directory (NEW 2020-10-10 - Version 1.5.2.1) - Download - General Help & Support - Example Scripts - Wiki
OutlookEX (NEW 2020-06-30 - Version 1.6.2.0) - Download - General Help & Support - Example Scripts - Wiki
OutlookEX_GUI (NEW 2020-06-27 - Version 1.3.2.0) - Download
Outlook Tools (2019-07-22 - Version 0.6.0.0) - Download - General Help & Support - Wiki
ExcelChart (2017-07-21 - Version 0.4.0.1) - Download - General Help & Support - Example Scripts
PowerPoint (2017-06-06 - Version 0.0.5.0) - Download - General Help & Support
Excel - Example Scripts - Wiki
Word - Wiki
Task Scheduler (2019-12-03 - Version 1.5.1.0) - Download - General Help & Support - Wiki

Tutorials:
ADO - Wiki, WebDriver - Wiki

 

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It's very simple in AutoIt script as opposed to most other scripting languages.

You can type in the function name into scite text editor and the click the name and press [F1], if you did it right, there should be a screen that pops up and tells you how to use it with an example.

Global $sFilePath = FileOpenDialog("Testing script",@ScriptDir, "All(*.*)",2+1)
If @error Then
    MsgBox(64, "Info!", "You canceled the file selection.")
Else
    MsgBox(64, "Info!", "You selected a file!" & @CR & "FilePath: """ & $sFilePath & """")
EndIf

; the """" sequence icludes one single " in the string, the "" acts as the  (escape character) would in most other languages...

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