Declaring multi dimentional arrays

[jorgepr13]

Is there is a way to do this

$arr[2][2] = [[1, 2], [3, 4]]

but something like this?

$arr[2][2]
$arr[0][2]=[1,2]
$arr[1][2]=[3,4]

because declaring it like this may take a lot of space

$arr[2][2]
$arr[0][0]=1
$arr[0][1]=2
$arr[1][0]=3
$arr[1][1]=4

in the case that you don't want to have all the declarations in the same place that it may look messy and may confuse not knowing in what dimension you are

Edited August 10, 2012 by jorgepr13

[water]

No, you can't do it the way you described above.

But if you want to fill the array with ascending numbers (1,2,3,4,5...) you can do it in a loop.

[jdelaney]

You can always do array in arrays, kind of array^2, rather than 2d array

#include <Array.au3>
Dim $aArray1[2] = [1,2]
Dim $aArray2[2] = [3,4]
Dim $aHouser[2] = [$aArray1,$aArray2]
For $i = 0 To UBound ( $aHouser ) - 1
   $currentArray = $aHouser[$i]
   _ArrayDisplay ( $currentArray )
Next

This has the advantage of only needing to know the 1 level of dimensions, as well

Edited August 10, 2012 by jdelaney

[jorgepr13]

the ascending/descending numbers are just for example

(sorry if I post it in the wrong place, I found other post with the same title here)

[water]

Be aware that the Array-in-Array-solution isn't recommended for performance reasons as you can read here at the end of the page.

[jorgepr13]

You can always do array in arrays, kind of array^2, rather than 2d array

#include <Array.au3>
Dim $aArray1[2] = [1,2]
Dim $aArray2[2] = [3,4]
Dim $aHouser[2] = [$aArray1,$aArray2]
For $i = 0 To UBound ( $aHouser ) - 1
$currentArray = $aHouser[$i]
_ArrayDisplay ( $currentArray )
Next

This has the advantage of only needing to know the 1 level of dimensions, as well

will it work for differentiated dimensions?

$arr[4][2]
$arr[0][2]=[1,2]
$arr[1][2]=[3,4]
$arr[2][2]=[1,4]
$arr[3][2]=[5,10]

Edited August 10, 2012 by jorgepr13

[jdelaney]

do whatever you want, but syntax must look like:

#include <Array.au3>
Dim $aArray1[2] = [1,2]
Dim $aArray2[2] = [3,4]
Dim $aArray3[2] = ["a","b"]
Dim $aArray4[3] = [3,4,5]
Dim $aArray5[2] = [9,10]

Dim $aHouser[5] = [$aArray1,$aArray2,$aArray3,$aArray4,$aArray5]
For $i = 0 To UBound ( $aHouser ) - 1
$currentArray = $aHouser[$i]
_ArrayDisplay ( $currentArray )
Next

edit: for your specific question, i'm thinking no

Edited August 10, 2012 by jdelaney

[AdmiralAlkex]

You can use the line continuation character ("_") to split long lines, example:

#include <Array.au3>

Local $arr[2][2] = [[1, 2], _
                    [3, 4]]

_ArrayDisplay($arr)

Edited August 10, 2012 by AdmiralAlkex