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johnmcloud

[SOLVED] Click outside the GUI

3 posts in this topic

#1 ·  Posted (edited)

Hi guys,

I want to know if a user clicks inside or outside the gui

For inside, is easy because i can use $GUI_EVENT_PRIMARYDOWN, but outside?

#include <GUIConstantsEx.au3>
#include <WindowsConstants.au3>
#include <StaticConstants.au3>
#include <Misc.au3>

Global $hGUI, $hDLL = DllOpen("user32.dll")

$Height = 550
$Width = 500

$hGUI = GUICreate("Test", $Height, $Width, -1, -1)
GUISetState()

While 1
_Click_Outside_and_Exit()
WEnd

Func _Click_Outside_and_Exit()
Local $pos = MouseGetPos()
If _IsPressed(01, $hDLL) Then
If $pos[0] > $Height Then
Exit
EndIf
If $pos[1] > $Width Then
Exit
EndIf
EndIf
If _IsPressed("1B", $hDLL) Then ; ESC
Exit
EndIf
EndFunc ;==>Test

I don't know if is a good approach, some advice?

Thanks

Edited by johnmcloud

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When a user clicks outside your GUI the window loses focus and is no longe the active window, right?

You could use WinActive to check.


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Yes, thanks, i don'0t have think about focus:

#include <GUIConstantsEx.au3>
#include <WindowsConstants.au3>
#include <StaticConstants.au3>
#include <Misc.au3>

Global $hGUI, $hDLL = DllOpen("user32.dll")

$Height = 550
$Width = 500

$hGUI = GUICreate("Test", $Height, $Width, -1, -1)
GUISetState()

While 1
_Click_Outside_and_Exit()
WEnd

Func _Click_Outside_and_Exit()
If _IsPressed(01, $hDLL) Then
  If Not WinActive($hGUI) Then
   Exit
  EndIf
EndIf
If _IsPressed("1B", $hDLL) Then ; ESC
  Exit
EndIf
EndFunc   ;==>_Click_Outside_and_Exit

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