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JackDinn

StringInStr ("testXa","x",0,-1) why = 5 not 1 ?

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$html="Mary had a little l/amb"

$test=StringInStr($html,"/",0,-1)

why $test=20 and not 4 ?

occurrence:- [optional] Which occurrence of the substring to find in the string. Use a negative occurrence to search from the right side. The default value is 1 (finds first occurrence).

im so dumb , what have i get wrong now ^_^ (it is late, no excuse)


Thx all,Jack Dinn.

 

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$html="Mary had a little l/amb"

$test=StringInStr($html,"/",0,-1)

why $test=20 and not 4 ?

occurrence:- [optional] Which occurrence of the substring to find in the string. Use a negative occurrence to search from the right side. The default value is 1 (finds first occurrence).

im so dumb , what have i get wrong now ^_^ (it is late, no excuse)

The returned character position is always left to right.

[center]Common sense plays a role in the basics of understanding AutoIt... If you're lacking in that, do us all a favor, and step away from the computer.[/center]

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$html="Mary had a little l/amb"

$test=StringInStr($html,"/",0,-1)

why $test=20 and not 4 ?

occurrence:- [optional] Which occurrence of the substring to find in the string. Use a negative occurrence to search from the right side. The default value is 1 (finds first occurrence).

im so dumb , what have i get wrong now ^_^ (it is late, no excuse)

I doesn't matter from which side you start to search a character - the result will always counted from the left side!

If you need it from right side just reverse the string:

#Include <string.au3>
$html="Mary had a little l/amb"
$test=StringInStr(_StringReverse($html),"/" ,0)
MsgBox(0,"test",$test)

UEZ


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I doesn't matter from which side you start to search a character - the result will always counted from the left side!

If you need it from right side just reverse the string:

#Include <string.au3>
$html="Mary had a little l/amb"
$test=StringInStr(_StringReverse($html),"/" ,0)
MsgBox(0,"test",$test)

UEZ

I think that _StringReverse() will be slower than StringLen().

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