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I know I can't be the only one looking for The time difference on a 9/80 secdual
(ie first week Mon-Thurs 9 hours, Fri 8 hours, second week Mon-Thu 9 hours Friday off)
Any pointer will help ( I have searched the form and haven't found what I want)

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I saw it.  What exactly are you trying to calculate/accomplish?

Maybe this is something to play with.

#include <date.au3>

Local $iYear = 2022
Local $iMonth = 1
Local $iDay = 2

For $i = 2 to 15
    Local $iHours = _Calculate9x80WorkHoursFromDate($iYear, $iMonth, $iDay)
    $sDayOfWeek = _DateDayOfWeek(_DateToDayOfWeek($iYear,$iMonth,$iDay),$DMW_LOCALE_LONGNAME)
    $sDate = StringFormat("%-24s", $iYear & "/" & $iMonth & "/" & $iDay & " (" & $sDayOfWeek & "): " )
    ConsoleWrite($sDate & ((IsNumber($iHours)) ? $iHours & " hours" : $iHours) & @CRLF)
    $iDay += 1
Next

Func _Calculate9x80WorkHoursFromDate($iYear, $iMonth, $iDay)
    ;Determine Day of the Week from Date YYYY MM DD
    $iWeekDay = _DateToDayOfWeek($iYear,$iMonth,$iDay)
    If @error Then Return -1

    Local $iHours = ""
    Switch $iWeekDay
        Case 2 To 5
            ;If Day of the Week is Monday - Thursday, Work hours is 9
            $iHours = 9
        Case 6
            ;If Day of the Week is Friday, Calculate work hours based on Week number - Odd Week's are Off Fridays; Even week's work hours are 8
            $iHours = (Mod(_WeekNumberISO($iYear, $iMonth, $iDay),2)) ? "Off Friday" : 8
        Case Else
            $iHours = "Off day"
    EndSwitch

    Return $iHours
EndFunc

 

Edited by spudw2k
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