StringSplit / StringTrimRight......?

[telmob]

Sorry if this question sounds noobish, but i'm trying to extract some filenames from a list and i'm unable to do it so far.

I have this:

C:picture1.jpg

C:picture2.jpg

And i want to extract this:

picture1.jpg

picture2.jpg

So... for example

$sString = "c:image.jpg"
StringSplit($sString, "")
$result=StringTrimRight.....??? I'm lost here.
MsgBox(0, "Result", $result)

The path varies, and i want to extract the extension and file name from right to left until it reaches the ''.

Edited November 19, 2012 by telmob

[Melba23]

telmob,

This should extract the filename and extension from any path:

Global $aPath[4] = ["C:picture1.jpg", "C:picture2.jpg", "D:anyPathpicture3.jpg", "Z:AndAnotherOnepicture4.jpg"]

For $i = 0 To 3
    $sFileNameExt = StringRegExpReplace($aPath[$i], "^.*", "")
    MsgBox(0, "Result", $aPath[$i] & @CRLF & @CRLF & $sFileNameExt)
Next

All clear?

M23

[telmob]

See... you lost me at StringRegExpReplace

Fantastic.

Once again you helped me out. Thank you so much Melba.

[Melba23]

telmob,

Allow me to explain:

^   - Start at the beginning of the string
.*  - Look for any number of characters until we find
  - a "" (we need to escape it with another )

""  - And replace all that with nothing

Because SREs are naturally "greedy", they always take the final "" of the path as the one to use and so just leave the filename and extension.

Clearer now?

M23

[JohnOne]

Using you own code, here is how you would do it.

$sString = "c:image.jpg"

$astringsplit = StringSplit($sString, "")

MsgBox(0, "Result", $astringsplit[ $astringsplit[0] ]) ; $astringsplit[0] is the last element in the array

[telmob]

whoo... very nice.

Much clearer now. I'll 'favoritize' stringregexp, it seems it will come in handy many times.

  On 11/19/2012 at 2:03 PM, 'JohnOne said:

Using you own code, here is how you would do it.

$sString = "c:image.jpg"

$astringsplit = StringSplit($sString, "")

MsgBox(0, "Result", $astringsplit[ $astringsplit[0] ]) ; $astringsplit[0] is the last element in the array

Seems easier to understand.

Thank you both Melba and John, terrific help.

[saywell]

What about using _PathSplit ?

William

[telmob]

Also very interesting

(sorry for the late reply)

Thank you.

[guinness]

What about StringInStr and StringTrimLeft as well?

Local $sFilePath = 'C:Picture.jpg'
ConsoleWrite(StringTrimLeft($sFilePath, StringInStr($sFilePath, '', 2, -1)) & @CRLF)

[kylomas]

Building on M23's example

#include<array.au3>

local $file_list = '"C:picture1.jpg, C:picture2.jpg", D:anyPathpicture3.jpg, "Z:AndAnotherOnepicture4.jpg"'
local $file_names_array = stringregexp($file_list,'(?i)(?U).*(w+.w+)[",]',3)

_arraydisplay($file_names_array)

note - I do NOT know how to get the last entry if the final quote is missing.

kylomas

[telmob]

I've solved this in the first example.

You guys rock!