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Hey so I was wondering if I had a file string such as "C:/example/file.exe" would there be any way to pull out the directory from that so I could set a variable to be "C:/example/" only knowing "C:/example/file.exe" automatically?

So for example, If I had this script:

Opt("MustDeclareVars", 1)
Global $file1
Global $directory1

$file1 = FileOpenDialog ("", "", "All Files (*.*)")

how would I be able to set $directory1 as the directory containing selected $file1

Edited by cheeseandcereal
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You could use function _PathSplit ore use a regular expression (some examples can be found on the forum).

My UDFs and Tutorials:

Spoiler

UDFs:
Active Directory (NEW 2021-06-05 - Version 1.5.4.0) - Download - General Help & Support - Example Scripts - Wiki
OutlookEX (NEW 2021-06-14 - Version 1.6.5.0) - Download - General Help & Support - Example Scripts - Wiki
OutlookEX_GUI (2021-04-13 - Version 1.4.0.0) - Download
Outlook Tools (2019-07-22 - Version 0.6.0.0) - Download - General Help & Support - Wiki
ExcelChart (2017-07-21 - Version 0.4.0.1) - Download - General Help & Support - Example Scripts
PowerPoint (2017-06-06 - Version 0.0.5.0) - Download - General Help & Support
Excel - Example Scripts - Wiki
Word - Wiki
Task Scheduler (2019-12-03 - Version 1.5.1.0) - Download - General Help & Support - Wiki

Tutorials:
ADO - Wiki, WebDriver - Wiki

 

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