SRE / RegExp : how to get enumerated strings

[mLipok]

I have a text

  Quote

===> Caption
1. first enumerated string

2. second enumerated string

....

x. "x-th" enumerated string

some other text

 

How to get this all enumerated string or entire lines ?

Remarks

first line which not start with number ends the enumeration

eace enumerated string is single line (no other line beetwen enumeration)

[jguinch]

Not sure to understand your request...

#Include <Array.au3>

$sContent = "1. first enumerated string" & @CRLF & _
            "2. second enumerated string" & @CRLF & _
            "3. third enumerated string" & @CRLF & _
            "4. fourth enumerated string" & @CRLF & _
            "5. fifth enumerated string" & @CRLF & _
            "some other text"

$aEnum = StringRegExp( StringRegExpReplace($sContent, "(?s)\R\D.*", ""), "(?m)^\d[\h.]*(\N+)", 3)

_ArrayDisplay($aEnum)

Do you need the number to be include to the result ?

[mLipok]

Works well

No I do not need the numbers.

But such example would be interesting for learning.

Thanks

mLipok

[jguinch]

To get the full line (with numbers) just use (?m)(N+) or something else...

[mikell]

jguinch, doesn't

$aEnum = StringRegExp($sContent, '(?m)^\d[\h.]*(\N+)', 3)

suffice ?

[kylomas]

or this...???

#Include <Array.au3>

$sContent = "1. first enumerated string" & @CRLF & _
            "2. second enumerated string" & @CRLF & _
            "3. third enumerated string" & @CRLF & _
            "4. fourth enumerated string" & @CRLF & _
            "5. fifth enumerated string" & @CRLF & _
            "some other text"

$aEnum = StringRegExp($sContent, "\d+\N+", 3)

_ArrayDisplay($aEnum)

[jguinch]

@mikell & kylomas : did you read the remarks in the first message ?

  On 1/16/2015 at 12:40 PM, mLipok said:

Remarks

first line which not start with number ends the enumeration

eace enumerated string is single line (no other line beetwen enumeration)

 

The text could be something like this :

$sContent = "1. first enumerated string" & @CRLF & _
            "2. second enumerated string" & @CRLF & _
            "3. third enumerated string" & @CRLF & _
            "4. fourth enumerated string" & @CRLF & _
            "5. fifth enumerated string" & @CRLF & _
            "some other text" & @CRLF & _
            "6. sixth enumerated string"

So if I understand the original post, the sixth element should not be part of the return...

Edited January 16, 2015 by jguinch

[mikell]

Question of interpretation  

Clarification in requirements needed - as usual

[mLipok]

  On 1/16/2015 at 8:13 PM, jguinch said:

@mikell & kylomas : did you read the remarks in the first message ?

 

The text could be something like this :

$sContent = "1. first enumerated string" & @CRLF & _
            "2. second enumerated string" & @CRLF & _
            "3. third enumerated string" & @CRLF & _
            "4. fourth enumerated string" & @CRLF & _
            "5. fifth enumerated string" & @CRLF & _
            "some other text" & @CRLF & _
            "6. sixth enumerated string"

So if I understand the original post, the sixth element should not be part of the return...

You understand it good.

btw.

I forget to say the enumeration starts with this caption.

  Quote

 

===> Caption

[jguinch]

$aEnum = StringRegExp( StringRegExpReplace($sContent, "(?s).*===> Caption(.*?)\R\D.*", "$1"), "(?m)^\d[\h.]*(\N+)", 3)

[mikell]

StringRegExpReplace($sContent, '(?s)(.*Caption\D*|\R\D.*|(?<=\v)\d\.\h)', "")