StringRegExpReplace - "replace" parameter

[mLipok]

I have such snippet:
 

_Example()

Func _Example()
    Local $sText = '"10.9"'
    MsgBox(0, '',  _
    StringRegExpReplace($sText,'("\d+\.)(\d)(")','$1$20$3') _
    )
EndFunc

I was trying to add 0 after 9.
I know that $20 is treated as group #20 not as group #2 and zero.

My question is:
How to insert 0 between $2 and $3 ?

 

[mikell]

Like this :    '$1${2}0$3'

BTW in this particular case, what about StringFormat ?  

[FrancescoDiMuro]

@mLipok

  Quote

Remarks

To separate back-reference replacements from actual (replaced) numbers, wrap them with curly braces, i.e: "${1}5".

Expand  

So:

_Example()

Func _Example()
    Local $sText = '"10.9"'
    MsgBox(0, '', StringRegExpReplace($sText,'("\d+\.)(\d)(")','$1${2}0$3'))
EndFunc

Maybe a StringFormat could be more appropriate?

[mLipok]

Thanks for answer.

btw.
There is a saying: The darkest place is under the lantern.

I was searching in:
https://www.autoitscript.com/autoit3/files/beta/autoit/docs/functions/StringRegExp.htm
instead:
https://www.autoitscript.com/autoit3/files/beta/autoit/docs/functions/StringRegExpReplace.htm

 

[FrancescoDiMuro]

  On 7/17/2019 at 12:38 PM, mLipok said:

There is a saying: The darkest place is under the lantern.

Expand  

Another thing learned today